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larisa86 [58]
3 years ago
8

1. Decomposition reactions can be classified into three types. Pick the correct

Chemistry
1 answer:
Alex777 [14]3 years ago
3 0

Answer:

Explanation:

Option A is the correct answer

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Which of the following are behaviors of a gas that can be explained by the kinetic-molecular theory?
My name is Ann [436]

Answer:

b,c,d

Explanation:

gasses exert pressure, all particles of a gas sample move at the same speed. gas particles can exchange kinetic energy when they collide.

7 0
3 years ago
Sodium nitrate and lead (ii) acetate express your answer as a chemical equation. identify all of the phases in your answer. ente
ICE Princess25 [194]

Answer: 2NaNO_3(aq)+(CH_3COO)_2Pb(aq)\rightarrow 2CH_3COONa(aq)+Pb(NO_3)_2(aq)

Explanation: A double displacement reaction is one in which exchange of ions take place.

The compounds which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

Thus the exchange of ions take place and all the compounds are soluble so the chemical formulas are followed by the symbol (aq).

3 0
3 years ago
Read 2 more answers
If the sample contained 2.0 moles of KClO3 at a temperature of 214.0 °C, determine the mass of the oxygen gas produced in grams
Westkost [7]

Answer : The mass of the oxygen gas produced in grams and the pressure exerted by the gas against the container walls is, 96 grams and 1.78 atm respectively.

Explanation : Given,

Moles of KCl_3 = 2.0 moles

Molar mass of O_2 = 32 g/mole

Now we have to calculate the moles of MgO

The balanced chemical reaction is,

2KClO_3\rightarrow 2KCl+3O_2

From the balanced reaction we conclude that

As, 2 mole of KClO_3 react to give 3 mole of O_2

So, 2.0 moles of KClO_3 react to give \frac{2.0}{2}\times 3=3.0 moles of O_2

Now we have to calculate the mass of O_2

\text{ Mass of }O_2=\text{ Moles of }O_2\times \text{ Molar mass of }O_2

\text{ Mass of }O_2=(3.0moles)\times (32g/mole)=96g

Therefore, the mass of oxygen gas produced is, 96 grams.

Now we have to determine the pressure exerted by the gas against the container walls.

Using ideal gas equation:

PV=nRT\\\\PV=\frac{w}{M}RT\\\\P=\frac{w}{V}\times \frac{RT}{M}\\\\P=\rho\times \frac{RT}{M}

where,

P = pressure of oxygen gas = ?

V = volume of oxygen gas

T = temperature of oxygen gas = 214.0^oC=273+214.0=487K

R = gas constant = 0.0821 L.atm/mole.K

w = mass of oxygen gas

\rho = density of oxygen gas = 1.429 g/L

M = molar mass of oxygen gas = 32 g/mole

Now put all the given values in the ideal gas equation, we get:

P=1.429g/L\times \frac{(0.0821L.atm/mole.K)\times (487K)}{32g/mol}

P=1.78atm

Thus, the pressure exerted by the gas against the container walls is, 1.78 atm.

7 0
3 years ago
What are the errors in this table check all that apply
Marat540 [252]

Answer:

Cannot be determined

Explanation:

Hi there,

Could you please add an attachment of the table? We cannot tell what the errors are if there is no table.

4 0
3 years ago
Which molecule has a high specific heat?<br><br> a) C2H6<br> b) C2H6O<br> c) H2O
dem82 [27]
H2O is the correct answer :)
4 0
3 years ago
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