Answer:
= 20.82 g of BaCl2
Explanation:
Given,
Volume = 200 mL
Molarity = 0.500 M
Therefore;
Moles = molarity × volume
= 0.2 L × 0.5 M
= 0.1 mole
But; molar mass of BaCl2 is 208.236 g/mole
Therefore; 0.1 mole of BaCl2 will be equivalent to;
= 208.236 g/mol x 0.1 mol
= 20.82 g
Therefore, the mass of BaCl2 in grams required is 20.82 g
Answer:
5.7*10^4 is equal to 57,000.
Explanation:
First, we must multiply 10 by its power, 4. That would be 10 4 times.
10*10*10*10 = 10,000.
Then, we multiply it by 5.7.
5.7*10,000 = 57,000.
Regards!
Answer:
the answer to number 9 is A.
Explanation:
Answer:
The Limiting Reactant is the reactant that when consumed the reaction stops.
Explanation: