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Pavlova-9 [17]
2 years ago
13

What is the molarity of 6 moles (mol) of NaCl dissolved in 2 L of water?

Chemistry
1 answer:
Mama L [17]2 years ago
8 0

Answer:

C:  \frac{6 mol}{2 L}

Explanation:

we can use the molarity equation

M = \frac{mol}{L}

so to find M we plug in what we know, which is 6 moles of NaCl and 2 L of water, which gives us:

\frac{6 mol}{2 L}

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A gas occupies a volume at 34.2 mL at a temperature of 15.0 C and a pressure of 800.0 torr. What will be the volume of this gas
Grace [21]
The answer is 34.1 mL.
Solution:
Assuming ideal behavior of gases, we can use the universal gas law equation
     P1V1/T1 = P2V2/T2
The terms with subscripts of one represent the given initial values while for terms with subscripts of two represent the standard states which is the final condition.
At STP, P2 is 760.0torr and T2 is 0°C or 273.15K. Substituting the values to the ideal gas expression, we can now calculate for the volume V2 of the gas at STP:
     (800.0torr * 34.2mL) / 288.15K = (760.0torr * V2) / 273.15K
     V2 = (800.0torr * 34.2mL * 273.15K) / (288.15K * 760.0torr)
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3 0
3 years ago
Read 2 more answers
In the reaction, A → Products, the rate constant is 3.6 × 10−4 s−1. If the initial concentration of A is 0.548 M, what will be t
Arada [10]

Answer:

        \large\boxed{\large\boxed{0.529M}}

Explanation:

Since the <em>rate constant</em> has units of <em>s⁻¹</em>, you can tell that the order of the reaction is 1.

Hence, the rate law is:

       r=d[A]/dt=-k[A]

Solving that differential equation yields to the well known equation for the rates of a first order chemical reaction:

      [A]=[A]_0e^{-kt}

You know [A]₀, k, and t, thus you can calculate [A].

       [A]=0.548M\times e^{-3.6\cdot 10^{-4}/s\times99.2s}

       [A]=0.529M

7 0
3 years ago
A sample of chromium oxide is 76.5hromium by weight. what is the simplest formula of the oxide?
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CrO and Cr₂O₃ make up the simplest chromium oxide formula.

What name does Cr₂O₃ use?

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Learn more about chromium here:

brainly.com/question/15588080

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6 0
1 year ago
A solution is prepared by dissolving 15.0 g of nh3 in 250.0 g of water. the density of the resulting solution is 0.974 g/ml. the
sergeinik [125]
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the solute here is NH₃ because it's the one with less amount. which makes water the solvent.

1) let's convert the grams of NH₃ to moles using the molar mass

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2) let's convert the grams of water into kilograms (just divide by 1000)

250.0 g= 0.2500 kg

3) let's plug in the values into the molality formula

molality= mol/ Kg---> 0.881 mol/ 0.2500 kg= 3.52 m
6 0
3 years ago
Which of the following is an oxidation? Select all that apply
butalik [34]

Answer:

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7 0
2 years ago
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