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3 years ago

Z varies directly with q. when z=2,q=1 . find a formula connecting z and q z=???

Mathematics

2 answers:

Lostsunrise [7]3 years ago

8 0

Answer:

$z = \frac{q}{2}$

Step-by-step explanation:

$z \infty q$

$z = kq$

$z = 2 \: and \: q = 1$

$2 = k1$

$k = \frac{2}{1}$

$z = \frac{1}{2} q$

$z = \frac{q}{2}$

attashe74 [19]3 years ago

5 0

9514 1404 393

Answer:

z = 2q

Step-by-step explanation:

The formula for direct variation is ...

z = kq . . . . . k is the constant of proportionality

We can find k using the given values of z and q:

k = z/q = 2/1 = 2

Then the equation connecting z and q is ...

z = 2q

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Find the x-intercepts, use the zero product property, r(r+7)=0

UkoKoshka [18]

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Answer:

r = 0

r = -7

Step-by-step explanation:

There is no x in the equation, hence there are no x-intercepts.

If we assume you want the values of r that satisfy the equation, the zero product property tells you they will be the values that make the factors zero.

The factors are r and (r+7).

The factor r is zero when ...

r = 0

The factor (r+7) is zero when ...

r +7 = 0 ⇒ r = -7

The "x-intercepts" are r=0 and r=-7.

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Vlad1618 [11]

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1 year ago

What is the common ratio for the geometric sequence 24 -6 3/2 -3/8

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3 years ago

Eric was rock climbing. At one point, he stopped and climbed straight down 2\dfrac{1}{2}2

nikitadnepr [17]

The equation that matches the given situation is $-2\frac{1}{2}+6\frac{3}{4}=?$ . So, after two moves, Eric's elevation changed $4\frac{1}{4}$ meters above.

We know that in mathematics, subtraction means removing something from a group or a number of things. What is left in the group gets smaller when we subtract. The minuend is the first element we use. The subtrahend is the part that is being removed. The difference is the portion that remains after subtraction.

Assume that "negative" means climbing down and "positive" means climbing up. We must locate the elevation change in this area.

Given that Eric climbed straight down $2\frac{1}{2}$ meters. So we can write $-2\frac{1}{2}$ .

Again Eric climbed straight up $6\frac{3}{4}$ meters. So, we can write $6\frac{3}{4}$ .

Then the change = $-2\frac{1}{2}+6\frac{3}{4}$

= $-\frac{(2*2+1)}{2}+\frac{6*4+3}{4}$

= $-\frac{5}{2} +\frac{27}{4}$

= $\frac{-(5*2)+27}{4}$

= $\frac{-10+27}{4}$

= $\frac{17}{4}$

= $\frac{4*4+1}{4}$

= $4\frac{1}{4}$

Therefore, the equation that matches the given situation is $-2\frac{1}{2}+6\frac{3}{4}=?$ . So, after two moves, Eric's elevation changed $4\frac{1}{4}$ meters above.

Learn more about subtraction here -

brainly.com/question/24116578

#SPJ10

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2 years ago