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AleksAgata [21]
3 years ago
10

How is filtration done? What is the difference between residue and filtrate?

Chemistry
1 answer:
LiRa [457]3 years ago
3 0

Answer:

residue is whatever remains after something else has been removed while filtrate is the liquid or solution that has passed through a filter, and which has been separated from the filtride.

filtration id done by placing a filter paper on the beaker or container then pour the filtride then let it settle and it will pass through and you will have the fitrate and residue

Explanation:

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10. Copper(i) bromide reacts with magnesium metal: 2 CuBr + Mg → 2 Cu + MgBrz
velikii [3]

Answer:

72.6 grams

Explanation:

I got this answer through stoichiometry.  For every 1 mole of Mg, 2 moles of CuBr are consumed.  Because of this, multiply the moles of Mg by 2.  Then, convert moles to grams.

5 0
3 years ago
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What volume of a 5.00M solution of hydrochloric acid contains 8.00mol of HCl?
rjkz [21]

Answer:

520ML and apparently I need to put more in this answer

Explanation:

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7 0
3 years ago
Methane gas reacts with oxygen in a gas stove.
nekit [7.7K]

Hey there!

CH₄ + 2O₂ → CO₂ + 2H₂O

carbon dioxide: product

methane: reactant

oxygen: reactant

water: product

Methane and oxygen are reactants because they are the substances we start with. They are on the side of the equation that the arrow is pointing away from.

Carbon dioxide and water are products because they are the new substances  that are the yields of the equation. They are on the side of the equation that the arrow is pointing towards.

Hope this helps!

7 0
3 years ago
_____ numbers are based on the distribution of electrons in a molecule.
leva [86]

Answer:

oxidation

Explanation:

oxidation number are based on the distribution of electrons in a molecule

8 0
3 years ago
A solution was found to have a 15.6 % transmittance at 500 nm, its wavelength of maximum absorption, using a cell with a path le
Gnesinka [82]

For the absorbance of the solution in a 1.00 cm cell at 500 nm  is mathematically given as

A’ = 0.16138

<h3>What is the absorbance of the solution in a 1.00 cm cell at 500 nm?</h3>

Absorbance (A) 2 – log (%T) = 2 – log (15.6) = 0.8069

Generally, the equation for the Beer’s law is mathematically given as

A = ε*c*l

0.8069 = ε*c*(5.00 )

ε*c = 0.16138 cm-1

then for when ε*c is constant

l’ = 1.00

A’ = (0.16138 cm-1)*(1.00 cm)

A’ = 0.16138

In conclusion, the absorbance of the solution in a 1.00 cm cell at 500 nm is

A’ = 0.16138

Read more about Wavelength

brainly.com/question/3004869

7 0
2 years ago
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