<em>A chemist makes 330. mL of nickel(II) chloride working solution by adding distilled water to 220. mL of a 0.135 mol/L stock solution of nickel(II) chloride in water. Calculate the concentration of the chemist's working solution. Round your answer to significant digits.</em>

Step 1: Given data

Initial concentration (C₁): 0.135 mol/L

Initial volume (V₁): 220. mL

Final concentration (C₂): ?

Final volume (V₂): 330. mL

Step 2: Calculate the concentration of the final solution

We prepare a dilute solution from a concentrated one. We can calculate the concentration of the working solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁/V₂

C₂ = 0.135 mol/L × 220. mL/330. mL = 0.0900 mol/L

3 0

2 years ago

A student would like to determine how heating a liquid changes its volume. The student hypothesizes that the liquid will increas

Zigmanuir [339]

Answer:

The volume of the liquid should be measured before it is heated.

Explanation:

3 0

3 years ago

PPLLLZZZ HHEEEELLLPPPP

masya89 [10]

Answer:

B) Cell Membrane

Explanation:

A) Chloroplasts are NOT in all cells, A is incorrect

C) Centrioles are for cell division, C is not correct

D) Cell walls are NOT in all cells, D is not correct

B) the cell membrane is responsible for materials traveling into and out of the cells to maintain homeostasis

5 0

3 years ago

The rate constant of a first order reaction is 0.035 sec-1. How much of a 1.5 M sample of reactant would remain after 28 seconds

andrey2020 [161]

Answer:

0.56 M

Explanation:

Step 1: Given data

Rate constant (k): 0.035 s⁻¹

Initial concentration of the reactant ([A]₀): 1.5 M

Time elapsed (t): 28 s

Step 2: Calculate the amount of reactant ([A]) after 28 seconds

For a first-order kinetics, we will use the following expression.

ln [A] = ln [A]₀ - k × t

ln [A] = ln 1.5 - 0.035 s⁻¹ × 28 s

[A] = 0.56 M

4 0

2 years ago