Which of the following was NOT explained by Dalton's atomic theory?

An atom of 105In has a mass of 104.914558 amu. Calculate the binding energy in MeV per NUCLEON. Enter your answer with 3 signifi

joja [24]

Answer:

8.46

Explanation:

Atomic number : It is defined as the number of electrons or number of protons present in a neutral atom.

Also, atomic number of I = 549

Thus, the number of protons = 49

Mass number is the number of the entities present in the nucleus which is the equal to the sum of the number of protons and electrons.

Mass number = Number of protons + Number of neutrons

105 = 49 + Number of neutrons

Number of neutrons = 56

Mass of neutron = 1.008665 amu

Mass of proton = 1.007825 amu

Calculated mass = Number of protons*Mass of proton + Number of neutrons*Mass of neutron

Thus,

Calculated mass = (49*1.007825 + 56*1.008665) amu = 105.868665 amu

Mass defect = Δm = |105.868665 - 104.914558| amu = 0.954107 amu

The conversion of amu to MeV is shown below as:-

1 amu = 931.5 MeV

So, Energy = 0.954107*931.5 MeV/atom = 888.750671 MeV/atom

Also, 1 atom has 105 nucleons (Protons+neutrons)

So, Energy = 888.750671 MeV/105nucleons = 8.46 MeV/nucleon

Answer:- 8.46

8 0

3 years ago

What is the name of the compound CO?\

xxTIMURxx [149]

Carbon Monoxide is the correct answer

4 0

3 years ago

Read 2 more answers

Which of the following is a measure of the average kinetic energy of the particles in a sample of matter?

cestrela7 [59]

Answer:

Option D. temperature

Explanation:

Indeed it is generally established that temperature is a measure of the kinetic energy ot the particles.

The kinetic energy of a particle is proportional to the product of the mass and the square of the speed. Mathematically, the kinetic energy, KE, is:

KE = (1/2) m × v²

Where m is the mass and v the speed of the particle.

In a sample of matter, not all the particles have the same speed, hence not all the particles have the same kinetic energy.

The kinetic energy and the temperature are related by the Boltzman equation:

KE = (3/2)KT

Where K is a constant (Boltzman constant) and T is the absolute temperature.

Therefore, as you can see from the last equation, the temperaure is a measure of the averate kinetic energy of the particles in a sample of matter.

This is, at a certain temperature, every substance has the same average kinetic energy.

7 0

3 years ago

Ammonia, NH3, is used as a refrigerant. At its boiling point of –33 oC, the standard enthalpy of vaporization of ammonia is 23.3

mario62 [17]

Answer:

-68.4 kJ

Explanation:

The standard enthalpy of vaporization = 23.3 kJ/mol

which means the energy required to vaporize 1 mole of ammonia at its boiling point (-33 °C).

To calculate heat released when 50.0 g of ammonia is condensed at -33 °C.

This is the opposite of enthalpy of vaporization which means that same magnitude of heat is released.

Thus, Q = -23.3 kJ/mol

Where negative sign signifies release of heat

Given: mass of 50.0 g

Molar mass of ammonia = 17.034 g/mol

Moles of ammonia = 50.0 /17.034 moles = 2.9353 moles

Also,

1 mole of ammonia when condenses at -33 °C releases 23.3 kJ

2.9412 moles of ammonia when condenses at -33 °C releases 23.3×2.9353 kJ

Thus, amount of heat released when 50 g of ammonia condensed at -33 °C= -68.4 kJ, where negative sign signifies release of heat.

4 0

3 years ago

What volume (mL) of 0.135 M NaOH is required to neutralize 13.7 mL of 0.129 M HCl? a: 0.24 b: 13.1 c: 0.076 d: 6.55 e: 14.3

Len [333]

Answer:

The volume (mL) of 0.135 M NaOH that is required to neutralize 13.7 mL of 0.129 M HCl is 13.1 mL (option b).

Explanation:

The reaction between an acid and a base is called neutralization, forming a salt and water.

Salt is an ionic compound made up of an anion (positively charged ion) from the base and a cation (negatively charged ion) from the acid.

When an acid is neutralized, the amount of base added must equal the amount of acid initially present. This base quantity is said to be the equivalent quantity. In other words, at the equivalence point the stoichiometry of the reaction is exactly fulfilled (there are no limiting or excess reagents), therefore the numbers of moles of both will be in stoichiometric relationship. So:

V acid *M acid = V base *M base

where V represents the volume of solution and M the molar concentration of said solution.

In this case:

V acid= 13.7 mL= 0.0137 L (being 1,000 mL= 1 L)
M acid= 0.129 M
V base= ?
M base= 0.135 M

Replacing:

0.0137 L* 0.129 M= V base* 0.135 M

Solving:

$V base=\frac{0.0137 L*0.129 M}{0.135 M}$

V base=0.0131 L = 13.1 mL

The volume (mL) of 0.135 M NaOH that is required to neutralize 13.7 mL of 0.129 M HCl is 13.1 mL (option b).

4 0

3 years ago