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ololo11 [35]
3 years ago
5

The area of a rooftop can be expressed as 9x^2+6x+1. The rooftop is a quadrilateral.

Mathematics
1 answer:
babymother [125]3 years ago
7 0

Part A: The type of the quadrilateral of the rooftop is a square

Part B: The length of one side of the rooftop is 19 m

Step-by-step explanation:

Let us revise some notes about quadratic expression

  • (a + b)² = a² + 2ab + b², where a² + 2ab + b² is a perfect square trinomial because it gives square binomial (a + b)²
  • Area of a square can be represented by perfect square trinomial, where the side of the square represented by the binomial

The area of a rooftop can be expressed as 9x² + 6x +1

The rooftop is a quadrilateral

We need to find the type of the quadrilateral and the length of

one side of the rooftop

∵ The area of the rooftop = 9x² + 6x +1

- Check if 9x² + 6x +1 is a perfect trinomial

∵ \sqrt{9x^{2}}=3x

∵ \sqrt{1}=1

∵ (3x)(1)(2)=6x

∴ 9x² + 6x +1 = (3x + 1)²

∴ 9x² + 6x +1 is a perfect square trinomial

∵ Perfect square trinomial can represent the area of a square

∴ The quadrilateral is a square

Part A: The type of the quadrilateral of the rooftop is a square

∵ The area of the rooftop is 9x² + 6x +1

∵ 9x² + 6x +1 = (3x + 1)²

∵ Area of the rooftop = 361 m²

∴ (3x + 1)² = 361

- Take square root for both sides

∴ 3x + 1 = 19

∵ The area of a square = (side)²

∵ The area of a square = (3x + 1)²

∴ 3x + 1 is the length of the side of the square

∵ 3x + 1 = 19

∴ The length of the side of the square is 19 m

Part B: The length of one side of the rooftop is 19 m

Learn more:

You can learn more about perfect square trinomial in brainly.com/question/7932185

#LearnwithBrainly

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In order to estimate the difference between the average hourly wages of employees of two branches of a department store, two ind
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Answer:

Step-by-step explanation:

Hello!

You have two populations of interest and want to compare them. If you define the study variables as:

X₁: average hourly wages of an employee of the Downtown store.

n₁= 25

X[bar]₁= $9

S₁= $2

X₂: average hourly wages of an employee of the North Mall store.

n₂= 20

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Both samples taken are independent, assuming that both populations are normal and that their population variances are equal I'll use the Student's-t statistic with a pooled sample variance to calculate the Confidence interval:

95% CI for μ₁ - μ₂

(X[bar]₁-X[bar]₂) ± t_{n_1+n_2-2; 1-\alpha /2} * (Sa*\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } )

Sa^2= \frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2}

Sa^2= \frac{24*4+19*1}{25+20-2}= 2.67

Sa= 1.64

t_{n_1-n_2-2;1-\alpha /2} = t_{43; 0.975} = 2.017

(9-8)±2.017*(1.64*\sqrt{\frac{1}{25} +\frac{1}{20} } )

[0.007636;1.9923]

I hope it helps!

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