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andrey2020 [161]
3 years ago
9

Can I have help with this. I'm really stuck. thanks. the question is above.​

Chemistry
1 answer:
evablogger [386]3 years ago
3 0

Answer:

The density of gallium would be greater than aluminium and boron.

Explanation:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Symbol:

The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.

As we move down the group densities increases because larger increase in mass occur with increase ion volume and greater sizes of elements down the group.

The boron, aluminium and gallium present in group thirteen. Boron is present in period two aluminium is present in period three and gallium is present in period four. So, atomic number of gallium is greater than boron and aluminium and it is appear as we move down the group. that's why gallium has larger size and greater value of density then boron and aluminium.

The value of density of gallium is 5.904 g/cm³.

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Answer:

1. 2NaN₃(s) → 2Na(s) + 3N₂(g)

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Explanation:

The answer is incomplete, as it is missing the required values to solve the problem. An internet search shows me these values for this question. Keep in mind that if your values are different your result will be different as well, but the solving methodology won't change.

" The airbags that protect people in car crashes are inflated by the extremely rapid decomposition of sodium azide, which produces large volumes of nitrogen gas. 1. Write a balanced chemical equation, including physical state symbols, for the decomposition of solid sodium azide (NaN₃) into solid sodium and gaseous dinitrogen. 2. Suppose 71.0 L of dinitrogen gas are produced by this reaction, at a temperature of 16.0 °C and pressure of exactly 1 atm. Calculate the mass of sodium azide that must have reacted. Round your answer to 3 significant digits. "

1. The <u>reaction that takes place is</u>:

  • 2NaN₃(s) → 2Na(s) + 3N₂(g)

2. We use PV=nRT to <u>calculate the moles of N₂ that were produced</u>.

P = 1 atm

V = 71.0 L

n = ?

T = 16.0 °C ⇒ 16.0 + 273.16 = 289.16 K

  • 1 atm * 71.0 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 289.16 K
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Now we <u>convert N₂ moles to NaN₃ moles</u>:

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Finally we <u>convert NaN₃ moles to grams</u>, using its molar mass:

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