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2 years ago

Describe the difference between pure substance and mixtures ( give an example each)

Chemistry

2 answers:

kondaur [170]2 years ago

4 0

Answer:

a pure substance consists only of one element or one compound

a mixture consists of two or more different substances, not chemically joined together.

examples:

pure substance : Hydrogen gas - Diamond - Gold metal.

mixture : water and oil - mixtures of sand and water - trail mix

Explanation:

forsale [732]2 years ago

4 0

Few examples of pure substances include steel, iron, gold, diamond, water, copper, and many more. Air is also often considered as a pure substance.

Some examples of mixtures are:

Sand and water.
Salt and water.
Sugar and salt.
Ethanol in water.
Air.
Soda.
Salt and pepper.
Solutions, colloids, suspensions.

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In 1860, Chemists could make which of the following statements about the known chemical elements?

LenKa [72]

Answer:

b. Some had similar properties

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3 years ago

The density of aluminium is 2.7 g/cm3. Find the mass in grams of a bar of aluminum measuring 2.7 cm by 1.2 cm by 14.3 cm.

Fofino [41]

Answer:125.0964g

Explanation:

Density = mass/volume

Density = 2.7 gcm-3

Volume=2.7*1.2*14.3=46.332

Mass=?

Mass= density* volume

= 2.7× 46.332=125.0964g

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3 years ago

Consider a general reaction

choli [55]

Answer:

a) K = 5.3175

b) ΔG = 3.2694

Explanation:

a) ΔG° = - RT Ln K

∴ T = 25°C ≅ 298 K

∴ R = 8.314 E-3 KJ/K.mol

∴ ΔG° = - 4.140 KJ/mol

⇒ Ln K = - ( ΔG° ) / RT

⇒ Ln K = - ( -4.140 KJ/mol ) / (( 8.314 E-3 KJ/K.mol )( 298 K ))

⇒ Ln K = 1.671

⇒ K = 5.3175

b) A → B

∴ T = 37°C = 310 K

∴ [A] = 1.6 M

∴ [B] = 0.45 M

∴ K = [B] / [A]

⇒ K = (0.45 M)/(1.6 M)

⇒ K = 0.28125

⇒ Ln K = - 1.2685

∴ ΔG = - RT Ln K

⇒ ΔG = - ( 8.314 E-3 KJ/K.mol )( 310 K )( - 1.2685 )

⇒ ΔG = 3.2694

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3 years ago

What is a potential risk of genetically modified food?

Ivahew [28]

It would be D since it could be unhealthy for you.

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3 years ago

Read 2 more answers

love history [14]

Answer : The molar concentration of sucrose in the tea is, 0.0549 M

Explanation : Given,

Mass of sucrose = 3.765 g

Volume of solution = 0.200 L

Molar mass of sucrose = 342.3 g/mole

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

$\text{Molarity}=\frac{\text{Mass of sucrose}}{\text{Molar mass of sucrose}\times \text{Volume of solution (in L)}}$

Now put all the given values in this formula, we get:

$\text{Molarity}=\frac{3.765g}{342.3g/mole\times 0.200L}=0.0549mole/L=0.0549M$

Therefore, the molar concentration of sucrose in the tea is, 0.0549 M

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3 years ago