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9966 [12]
3 years ago
13

A sample of a compound is analyzed and found to contain 0.420 g nitrogen, 0.480g oxygen, 0.540 g carbon and 0.135 g hydrogen. Wh

at is the empirical formula of the compound? a. C2H5NO b. CH3NO c. C3H9N2O2 d. C4HN3O4 e. C4H13N3O3
Chemistry
1 answer:
Crazy boy [7]3 years ago
7 0

Answer:

c. C3H9N2O2

Explanation:

The empirical formula of a compound is defined as the simplest whole number ratio of atoms present in a molecule. To solve this question we need to convert the mass of each atom to moles. With the moles we can find the ratio as follows:

<em>Moles N -Molar mass: 14.01g/mol-</em>

0.420g N * (1mol/14.01g) = 0.0300 moles N

<em>Moles O -Molar mass: 16g/mol-</em>

0.480g O * (1mol/16g) = 0.0300 moles O

<em>Moles C -Molar mass: 12.01g/mol-</em>

0.540g C * (1mol/12.01g) = 0.0450 moles C

<em>Moles H -Molar mass: 1.0g/mol-</em>

0.135g H * (1mol/1g) = 0.135moles H

Dividing in the moles of N (Lower number of moles) the ratio of atoms is:

N = 0.0300 moles N / 0.0300 moles N = 1

O = 0.0300 moles O / 0.0300 moles N = 1

C = 0.0450 moles C / 0.0300 moles N = 1.5

H = 0.135 moles H / 0.0300 moles N = 4.5

As the empirical formula requires whole numbers, multiplying each ratio twice:

N = 2, O = 2, C = 3 and H = 9

And the empirical formula is:

<h3>c. C3H9N2O2</h3>

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Which element in the third period would you expect to have the larger atomic radius, sodium (Na) or Sulfur (S)?
jeyben [28]

<u>Answer: </u>The correct answer is Option B.

<u>Explanation:</u>

The given elements that is sodium and sulfur are the elements which belong to the same period that is third period.

As, the electrons are added up to the same shell across a period, the number of protons also increase and hence, they attract the electrons more effectively. This means that the effective nuclear charge also increases and the size of the sulfur thus shrink and hence, the size (atomic radius) of sodium is the largest amongst third period.

Therefore, the correct answer is Option B.

7 0
3 years ago
Read 2 more answers
List all the ways you can change oceanic crust into continental crust using the sliders.<br> IS
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8 0
3 years ago
Consider the reaction PCl5(g) ⇌ PCl3(g) + Cl2(g). If 0.02 moles of PCl5, 0.04 moles of PCl3, and 0.08 moles of Cl2 are combined
Furkat [3]

Answer:

The reaction quotient (Q) before the reaction is 0.32

Explanation:

Being the reaction:

aA + bB ⇔ cC + dD

Q=\frac{[C]^{c} *[D]^{d} }{[A]^{a}*[B]^{b}  }

where Q is the so-called reaction quotient and the concentrations expressed in it are not those of the equilibrium but those of the different reagents and products at a certain instant of the reaction.

The concentration will be calculated by:

Concentration=\frac{number of moles of solute}{Volume}

You know  the reaction:

PCl₅ (g) ⇌ PCl₃(g) + Cl₂(g).

So:

Q=\frac{[PCl_{3} ] *[Cl_{2} ] }{[PCl_{5} ]}

The concentrations are:

  • [PCl₃]=\frac{0.04 moles}{0.5 L} =0.08 \frac{moles}{L}
  • [Cl₂]=\frac{0.08 moles}{0.5 L} =0.16 \frac{moles}{L}
  • [PCl₅]=\frac{0.02 moles}{0.5 L} =0.04 \frac{moles}{L}

Replacing:

Q=\frac{0.08*0.16}{0.04}

Solving:

Q= 0.32

<u><em>The reaction quotient (Q) before the reaction is 0.32</em></u>

4 0
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