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frez [133]
3 years ago
12

0.10 mol of argon gas is admitted to an evacuated 50 cm3 container at 20°C. The gas then undergoes heating at constant volume to

a temperature of 300°C. What is the final pressure of the gas? M - 106
Chemistry
1 answer:
dolphi86 [110]3 years ago
5 0

<u>Answer:</u> The final pressure of the gas is 9.41 atm

<u>Explanation:</u>

To calculate the pressure of the gas, we use the equation given by ideal gas equation:

PV=nRT

where,

P = pressure of the gas = ?

V = Volume of gas = 50cm^3=0.05L    (Conversion factor:  1L=1000cm^3 )

n = Number of moles = 0.01 mol

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = temperature of the gas = 300^oC=[300+273]K=573K

Putting values in above equation, we get:

P\times 0.050L=0.01\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 573K\\\\P=\frac{0.01\times 0.0821\times 573}{0.05}=9.41atm

Hence, the final pressure of the gas is 9.41 atm

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