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4 years ago

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0.10 mol of argon gas is admitted to an evacuated 50 cm3 container at 20°C. The gas then undergoes heating at constant volume to

a temperature of 300°C. What is the final pressure of the gas? M - 106

1 answer:

dolphi86 [110]4 years ago

5 0

<u>Answer:</u> The final pressure of the gas is 9.41 atm

<u>Explanation:</u>

To calculate the pressure of the gas, we use the equation given by ideal gas equation:

$PV=nRT$

where,

P = pressure of the gas = ?

V = Volume of gas = $50cm^3=0.05L$ (Conversion factor: $1L=1000cm^3$ )

n = Number of moles = 0.01 mol

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = temperature of the gas = $300^oC=[300+273]K=573K$

Putting values in above equation, we get:

$P\times 0.050L=0.01\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 573K\\\\P=\frac{0.01\times 0.0821\times 573}{0.05}=9.41atm$

Hence, the final pressure of the gas is 9.41 atm

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