2NH4Cl(aq) + Ba(OH)2(aq) -> BaCl2(aq) + 2NH3(aq) + 2H2O(1)

The production of iron and carbon dioxide from iron(iii) oxide and carbon monoxide is an exothermic reaction. which expression c

NARA [144]

Missing question:
A. [3.40 mol Fe2O3 (s) × 26.3 kJ/1 mol Fe2O3 (s)] / 2
B. 3.40 mol Fe2O3 (s) × 26.3 kJ/1 mol Fe2O3 (s) 
C. 26.3 kJ/1 mol Fe2O3 (s) / 3.40 mol Fe2O3 (s) 
D. 26.3 kJ/1 mol Fe2O3 (s) – 3.40 mol Fe2O3 (s).
Answer is: B.
Chemical reaction: Fe₂O₃(s) + 3CO(g) → 2Fe(s) + 3CO₂(g);ΔH = + 26.3 kJ.
When one mole of iron(III) oxide reacts 26,3 kJ of energy is required and for 3,2 moles of iron(III) oxide 3,2 times more energy is required.

8 0

3 years ago

Read 2 more answers

Is a situation in which a dominant allele completely masks a recessive allele for a gene.

Bond [772]

Complete dominance.... Hope this helps

4 0

3 years ago

Which of the following has 62 neutrons, 46 protons, and 46 electrons?

Vesna [10]

The answer is Silver (Ag)

6 0

3 years ago

Labels of many food products have expiration dates, at which point they are typically removed from the supermarket shelves. A pa

White raven [17]

Answer:

Explanation:

Since it first order, we use order rate equation

In ( $\frac{A1}{A0}$ ) = -kt where A1 is the final quality = 0.8 (80%), A0 is the initial quality = 1 ( 100%)

also, t half life = $\frac{In2}{k}$ where k is rate constant

k = $\frac{In 2}{45 days}$ = 0.0154

In ( $\frac{0.8}{1}$ ) = - 0.0154 t

-0.223 / -0.0154 = t

t = 14.49 approx 14.5 days from the date the yogurt was packaged

6 0

3 years ago

Calculate the reaction quotient Qp for the following redox reaction: 14H+ + Cr2O72- + 6Cl- ----> 2Cr3+ + 3Cl2 + 7H2O The reac

stich3 [128]

Answer:

Value of $Q_{p}$ for the given redox reaction is $1.0\times 10^{-8}$

Explanation:

Redox reaction with states of species:

$14H^{+}(aq.)+Cr_{2}O_{7}^{2-}(aq.)+6Cl^{-}(aq.)\rightarrow 2Cr^{3+}(aq.)+3Cl_{2}(g)+7H_{2}O(l)$

Reaction quotient for this redox reaction:

$Q_{p}=\frac{[Cr^{3+}]^{2}.P_{Cl_{2}}^{3}}{[H^{+}]^{14}.[Cr_{2}O_{7}^{2-}].[Cl^{-}]^{6}}$

Species inside third braket represent concentration in molarity, P represent pressure in atm and concentration of $H_{2}O$ is taken as 1 due to the fact that $H_{2}O$ is a pure liquid.

$pH=-log[H^{+}]$

So, $[H^{+}]=10^{-pH}$

Plug in all the given values in the equation of $Q_{p}$ :

$Q_{p}=\frac{(0.10)^{2}\times (0.010)^{3}}{(10^{-0.0})^{14}\times (1.0)\times (1.0)^{6}}=1.0\times 10^{-8}$

7 0

3 years ago