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3 years ago

I will mark you brainliest!!! What is the answer?

Mathematics

1 answer:

Furkat [3]3 years ago

3 0

Answer:

Step-by-step explanation:

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If q is the midpoint of segment PR, find the coordinates of R if P (11,-2) and Q (4,3)

Murrr4er [49]

Answer:

R(-3, 8)

Step-by-step explanation:

R = 2Q -P

R = 2(4, 3) -(11, -2) = (8-11, 6+2)

R = (-3, 8)

_____

You can derive the formula for the endpoint from the formula for the midpoint:

Q = (R + P)/2

R = 2Q - P . . . . . . multiply by 2 and subtract P

3 0

3 years ago

Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.

likoan [24]

Answer:

Thus, the two root of the given quadratic equation $x^2+4=6x$ is 5.24 and 0.76 .

Step-by-step explanation:

Consider, the given Quadratic equation, $x^2+4=6x$

This can be written as , $x^2-6x+4=0$

We have to solve using quadratic formula,

For a given quadratic equation $ax^2+bx+c=0$ we can find roots using,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ ...........(1)

Where, $\sqrt{b^2-4ac}$ is the discriminant.

Here, a = 1 , b = -6 , c = 4

Substitute in (1) , we get,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$\Rightarrow x=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot 1 \cdot (4)}}{2 \cdot 1}$

$\Rightarrow x=\frac{6\pm\sqrt{20}}{2}$

$\Rightarrow x=\frac{6\pm 2\sqrt{5}}{2}$

$\Rightarrow x={3\pm \sqrt{5}}$

$\Rightarrow x_1={3+\sqrt{5}}$ and $\Rightarrow x_2={3-\sqrt{5}}$

We know $\sqrt{5}=2.23607$ (approx)

Substitute, we get,

$\Rightarrow x_1={3+2.23607}$ (approx) and $\Rightarrow x_2={3-2.23607}$ (approx)

$\Rightarrow x_1={5.23607}$ (approx) and $\Rightarrow x_2=0.76393}$ (approx)

Thus, the two root of the given quadratic equation $x^2+4=6x$ is 5.24 and 0.76 .

7 0

3 years ago

Read 2 more answers

A scientist measured the amount of rain that fell in a town during

allochka39001 [22]

Answer:

1.47 mm

Step-by-step explanation:

In week 1 there was 2.6 mm

In week 4 there was 4.07

You want to find the difference of week 1 and 4 meaning you have to subtract week 4's value from week 1's to find how much more rain there was in week 4 than week 1

You would do 4.07-2.6

This is equal to 1.47

THEREFORE there was 1.47 mm more rain in week 4 than week 1

6 0

3 years ago

Is this a true statement? 0.3711 > 0.3801

disa [49]

NO. It's FALSE.

$0.\ 3\ 7\ 1\ 1\\||\ ||\wedge\\0.\ 3\ 8$

therefore 0.3801 > 0.3711

4 0

3 years ago

What is the value of x is in the solution set of 8x-6>12+2x?

fiasKO [112]

Answer:

see explanation

Step-by-step explanation:

Given

8x - 6 > 12 + 2x ( subtract 2x from both sides )

6x - 6 > 12 ( add 6 to both sides )

6x > 18 ( divide both sides by 6 )

x > 3

Any value of x greater than 3 will be in the solution set

7 0

3 years ago