Answer:
Proportional: second and third, non-proportional: first and fourth
Step-by-step explanation:
Proportional relationships are linear functions that pass through the origin. Using this definition, we can conclude that the proportional relationships are the second and third options whereas the non-proportional relationships are the first and fourth options.
A quadratic equation has the general formula
expressed as:<span>
ax^2 + bx - c = 0
This equation can be solved by the quadratic
formula which is expressed as:
x = ( -b (+ or -) √(b^2 - 4ac) / 2a
From the given equation, </span><span> y=-0.005x^2+0.41x-5.1
</span><span>
a = -0.005
b = 0.41
c = -5.1
Using the quadratic formula and the corresponding values of the coefficient, we substitute these and obtain:
</span>x = ( -b (+ or -) √(b^2 - 4ac) / 2a
x = ( -0.41 (+ or -) √(0.41^2 - 4(-0.005)(5.1)) / 2(-0.005)
x1 =66.71
x2 = 15.29
Therefore, the quadratic equation would be factored by using the values of x we obtained as follows:
<span>y= -0.005x^2 + 0.41x - 5.1
</span>y = (x - 66.71) ( x - 15.29 )
Answer:
y=2x-5
Step-by-step explanation:
the line equation
Answer:
Step-by-step explanation:
area of sector=πr²/4=π ×6²/4=9 π ft²
area of one triangle= 1/2×6×6=18 ft²
area of three triangles=3×18=54 ft²
area of sector +area of three triangles=54+9 π ft²
area of circle=π×6²=36 π ft²
area of shaded region=36 π-9π-54=27 π-54=27(π-2) ft²
Let's come up with an equation for the numbers. We know that there are 136 faculty members, and there are 6 professors for every 11 lecturers. The equation could look something like this:
(6 * x) + (11 * x) = 136.
First, combine like terms:
6x + 11x = 136
17x = 136
Now, divide both sides by 17.
17x/17 = 136/17
x = 8.
Now, to check, plug in 8 for x in our equation:
(6 * 8) + (11 * 8) = 136
48 + (11 * 8) = 136
48 + 88 = 136
So to answer the question, they have 48 professors! :)