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3 years ago

A zoo has some new exhibits.

Mathematics

1 answer:

Licemer1 [7]3 years ago

3 0

Answer

Elephant: 14%

Panda: 18%

Tiger: 29%

Bonobo: 39%:

Step-by-step explanation:

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How do I go about solving (27x^3/8y^9)^5/3? And what is the role of the numerator and denominator?

MrRissso [65]

$\left( \frac{27x^3}{8y^9}\right)^ \frac{5}{3} \\\\\\ =\left( \frac{(3x)^3}{(2y^3)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(3x)^{3 \times \frac{5}{3} }}{(2y^3)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(3x)^5}{(2y^3)^{5 }} \\\\\\ =\frac{243x^5}{32y^{15}}$

Now, If the exponent was negative like you asked....

$\left( \frac{27x^3}{8y^9}\right)^ {-\frac{5}{3}} \\\\\\ =\left( \frac{8y^9}{27x^3}\right)^ {\frac{5}{3}}\\\\\\ =\left( \frac{(2y^3)^3}{(3x)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(2y^3)^{3 \times \frac{5}{3} }}{(3x)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(2y^3)^{5 }}{(3x)^5} \\\\\\ =\frac{32y^{15}}{243x^5}$

5 0

3 years ago

En las competencias de atletismo hay 120 participantes; 30 en la prueba de 100 m, 50 en la de 200 m y 40 en la carrera de relevo

IceJOKER [234]

Answer:

120 by the questiom we have tl do plus or not

7 0

3 years ago

How do find length and width if you have the area?

chubhunter [2.5K]

Answer:

Step-by-step explanation:

The area of a rectangle(A) related to the length (L) and WITDH (W) of its sides by the following Relationship:A=L W if you know the width is easy to find the length rearranging this equation to get L=A÷w if you know the length and want width rearranged to get W=A÷L this is the formula not the answer.

5 0

4 years ago

HELP PLEASE

Rudiy27

Answer:

b : -3x+3

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

2x + 12 = -2(4-2x)<br> X=10<br> X=-10<br> X=-5<br> X=5

Greeley [361]

Answer:

$\boxed{x = 10}$

Step-by-step explanation:

$= > 2x + 12 = - 2(4 - 2x) \\ \\ = > 2x + 12 = (( - 2) \times 4) - (( - 2) \times 2x) \\ \\ = > 2x + 12 = - 8 - ( - 4x) \\ \\ = > 2x + 12 = - 8 + 4x \\ \\ = > 2x - 4x + 12 = - 8 \\ \\ = > - 2x + 12 = - 8 \\ \\ = > - 2x = - 8 - 12 \\ \\ = > \cancel{-} 2x = \cancel{- }20 \\ \\ = > 2x = 20 \\ \\ = > x = \frac{20}{2} \\ \\ = > x = 10$

6 0

3 years ago

Read 2 more answers