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2 years ago

8

Anna and her friends are making their own puzzles by drawing and painting on pieces of cardboard Anna cuts her puzzle so that th

ere are 12 rows and 15 columns how many pieces are in Anna's puzzle

1 answer:

vova2212 [387]2 years ago

6 0

Answer:

180, because you'd do 12 x 15

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Really need helpppp?!

user100 [1]

Answer:

6.43

pls follow me and mark brainliest ...thank u

Step-by-step explanation:

length of side x will be

Tan tita = opp/adjacent

tan65 = x/3

tan 65 is 2.14

so...you are left with 2.14=x/3

by cross multiplying

x= 2.14 × 3

= 6.43

5 0

3 years ago

Any help would be appreciated. (Check the picture)

White raven [17]

the answer would be 0.800375 but when you round it to the nearest tenth it would be 0.8

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3 years ago

2/4 notes equal to how many eighth notes

natali 33 [55]

Answer:

Two eighth notes equal one quater note in duration.

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Meghan is attending a college where tuition is $6,600 per year. She received a $2,000 grant and her parents will give her anothe

n200080 [17]

ANSWER:

Total fee per year = $6,600.

In which she have,

$2,000 + $1,500
$3,500

Now, we need to subtract it from total fee to get the remaining demand.

So, $6,600 - $3,500

$3,100

Hence, Meghan will have to earn __$3,100__ to pay for the first year tuition.

4 0

3 years ago

A healthcare provider monitors the number of CAT scans performed each month in each of its clinics. The most recent year of data

Rasek [7]

Answer: a. 1.981 < μ < 2.18

b. Yes.

Step-by-step explanation:

A. For this sample, we will use t-distribution because we're estimating the standard deviation, i.e., we are calculating the standard deviation, and the sample is small, n = 12.

First, we calculate mean of the sample:

$\overline{x}=\frac{\Sigma x}{n}$

$\overline{x}=\frac{2.31=2.09+...+1.97+2.02}{12}$

$\overline{x}=$ 2.08

Now, we estimate standard deviation:

$s=\sqrt{\frac{\Sigma (x-\overline{x})^{2}}{n-1} }$

$s=\sqrt{\frac{(2.31-2.08)^{2}+...+(2.02-2.08)^{2}}{11} }$

s = 0.1564

For t-score, we need to determine degree of freedom and $\frac{\alpha}{2}$ :

df = 12 - 1

df = 11

$\alpha$ = 1 - 0.95

α = 0.05

$\frac{\alpha}{2}=$ 0.025

Then, t-score is

$t_{11,0.025}$ = 2.201

The interval will be

$\overline{x}$ ± $t.\frac{s}{\sqrt{n} }$

2.08 ± $2.201\frac{0.1564}{\sqrt{12} }$

2.08 ± 0.099

The 95% two-sided CI on the mean is 1.981 < μ < 2.18.

B. We are 95% confident that the true population mean for this clinic is between 1.981 and 2.18. Since the mean number performed by all clinics has been 1.95, and this mean is less than the interval, there is evidence that this particular clinic performs more scans than the overall system average.

8 0

3 years ago