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dexar [7]
3 years ago
12

Each problem is worth 10 points each. (For each problem show your work and give a brief explanation of how you solved your probl

em.)
There are 5^12 blades of grass in each acre of land, and a section of land has 5^7 acres of land. How many blades of grass does the land have? Leave your answer in the for a^b and simplified form.

A swimming center builds a new pool that has the dimensions 3a^6 by a^2 by b^4. What is the volume of the pool?
Mathematics
1 answer:
maxonik [38]3 years ago
5 0
It’s a big problem it’s deserve 20 points you can’t play people make it fair
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Keith has 7 yards of string. He needs ⅓ yard of string for each of his puppets. How many puppets can Keith make with his string?
Pani-rosa [81]

Answer:

the no of puppets that could be made with his string is 21

Step-by-step explanation:

Given that

There is 7 yards

And, it needs one -third of string for each of his puppets

= 7 × 3

= 21 puppets

We simply multiply the 7 yards with the 3 so that the no of puppets could come

hence, the no of puppets that could be made with his string is 21

8 0
3 years ago
Line d is parallel to line c in the figure below Which statements about the figure are true? Select three options
Marianna [84]
Line d and c are bother parallel but the three options would be them
4 0
4 years ago
Georgianna claims that in a small city renowned for its music school, the average child takes at least 5 years of piano lessons.
Allisa [31]

Answer:

The  condition  are

           The  Null hypothesis is  H_o  :  \mu = 5

           The  Alternative hypothesis is  H_a  :  \mu <  5

The  check revealed that

             There is sufficient evidence to support the claim that in a small city renowned for its music school, the average child takes at least 5 years of piano lessons

Step-by-step explanation:

From the question we are told that

     The  population mean is  \mu =  5 \ year

      The sample size is  n =  20

      The sample mean is  \=  x  =  4.6 \  years

       The  standard deviation is \sigma  =  2.2  \ years

   The  Null hypothesis is  H_o  :  \mu = 5

   The  Alternative hypothesis is  H_a  :  \mu <  5

So i will be making use of  \alpha =  0.05 level of significance to test this claim

    The critical value of  \alpha from the normal distribution table is  Z_\alpha  =  1.645

 

Generally the test statistics is mathematically evaluated as

                 t =  \frac{\= x  - \mu}{ \frac{\sigma }{\sqrt{n} } }

substituting values

                 t =  \frac{ 4.6  - 5}{ \frac{2.2}{\sqrt{20} } }

                t =  -0.8131

Looking at the value of  t and Z_{\alpha } we see that  t <  Z_{\alpha } so we fail to reject the null hypothesis  

  This implies that there is sufficient evidence to support the claim that in a small city renowned for its music school, the average child takes at least 5 years of piano lessons.

4 0
3 years ago
What is the mean, outlier &amp; mean without outlier for 4; 4; 5; 6; 8; 9; 27
aleksley [76]

Answer:

the mean is 9.

Step-by-step explanation:

<h2>mean=<u>4+4+5+6+8+9+27</u></h2>

7

<h2>= <u>63</u></h2><h2> 7</h2><h2> 9 is the answer.</h2>

5 0
3 years ago
Please help. Flow chart proof. I'll give brainliest
AveGali [126]

Step-by-step explanation:

Statement | Reason

CB=AB         Given

DBC=DBA   Given

DB = DB      Reflexive Property

/_\ DBC

=~

/_\DBA        SAS

Sorry for the formatting the =~ means congruent.

4 0
2 years ago
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