The second garden plot will require 8√5 feet more fence than the first garden plot.
Further explanation:
In order to find the fence, we have to find the perimeter of both squares
So,
Area of Square 1: A1=180 square feet
Area of Square 2: A2=320 Square feet
Let x be the side of square 1:
Then,

For second square:
Let y be the side of second square

Perimeter of First Square:

Perimeter of Second Square:

The smaller perimeter will be subtracted from larger perimeter to find that how much more fence will be needed.

The second garden plot will require 8√5 feet more fence than the first garden plot.
Keywords: Radicals, Operations on Radicals
Learn more about radicals at:
#LearnwithBrainly
Answer:
(x-4) is not a factor of f(x)=x³-2x²+5x+1
Step-by-step explanation:
Uding the remainder theorem,(x-4) is a factor if the remainder is 0
Plug in x=4
(4)³-2(4)²+5(4)+1
64-32+20+1
64-53
11
Answer: It would be a Constant variable.
Hope this helps!
Answer:
44.16 ; 4.88
Step-by-step explanation:
Recall :
Mean, μ = np
Sample size, n = 96
Sample proportion, p = 0.46
For the mean :
Mean, μ = 96 * 0.46
0.46 * 96 = 44.16
The standard deviation :
σ = √npq
q = 1 - p = 1 - 0.46 = 0.54
σ = √npq = √(96 * 0.46 * 0.54)
σ = √23.8464
σ = 4.88