Answer:
u" + 40u' + 49u = 2 sin(t/6)
upp + 40up + 49u = 2 sin(t/6)
Explanation:
Step 1: Data given
mass = 5 kg
L = 20 cm = 0.2 m
F = 10 sin(t/6)N
Fd(t) = - 6 N
u(0) = 0.03 m/s
u(0) = 0
u'(0) = 3 cm/s
Step 2:
ω =kL
k = ω/L = m*g /L = (5*9.8)/0.2 = 245 kg/s²
Since Fd(t) = -γu'(t) we know:
γ =- Fd(t) / u'(t) = 6N/ 0.03 m/s = 200 Ns/m
The initial value problem which describes the motion of the mass is given by
5u" + 200u' + 245u = 10 sin(t/6) u(0) = 0 ; u'(0) = 0.03
This is equivalent to:
u" + 40u' + 49u = 2 sin(t/6) u(0) = 0 ; u'(0) = 0.03
upp + 40up + 49u = 2 sin(t/6)
With u in m and t in s
Answer: a disadvantage of using a ramp is that it is not safe
<h2><u>Answer:</u></h2>
Accordingly, when our Sun comes up short on hydrogen fuel, it will grow to end up a red monster, puff off its external layers, and after that settle down as a minimal white small star, at that point gradually chilling off for trillions of years.
All incredible, in the long run — in around 5 billion years — our sun will, as well. When its supply of hydrogen is depleted, the last, sensational phases of its life will unfurl, as our host star extends to wind up a red goliath and afterward shreds its body to consolidate into a white smaller person
Explanation:
acceleration = change in velocity / change in time
a = v2-v1
- - - - - -
t
V1 = 0 ( since she stopped)
V2 = 9 m/s
t =15s
a = 9 - 0
- - - -
15
= 0.6m/s^2
Answer:
A) Concentration of A left at equilibrium of we started the reaction with [A] = 2.00 M and [B] = 2.00 M is 0.55 M.
B) Final concentration of D at equilibrium if the initial concentrations are [A] = 1.00 M and [B] = 2.00 M is 0.90 M.
[D] = 0.90 M
Explanation:
With the first assumption that the volume of reacting mixture doesn't change throughout the reaction.
This allows us to use concentration in mol/L interchangeably with number of moles in stoichiometric calculations.
- The first attached image contains the correct question.
- The solution to part A is presented in the second attached image.
- The solution to part B is presented in the third attached image.
