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Ganezh [65]
2 years ago
13

A hair dryer is basically a duct of constant diameter in which a few layers of electric resistors are placed. A small fan pulls

the air in and forces it through the resistors where it is heated. If the density of air is 1.20 kg/m3 at the inlet and 1.015 kg/m3 at the exit, determine the percent increase in the velocity of air as it flows through the dryer
Physics
1 answer:
Mars2501 [29]2 years ago
5 0

Answer:

Therefore % increase in velocity is 18.23 %

Explanation:

we use the equality of mass flow rate and the areas

m_1 = m_2\\p_1v_1 = p_2v_2\\p_1A_1v_1 = p_2A_2v_2\\v_2 = \frac{p_1}{p_2} v_1

The percentage increase in velocity is

Δ v% = \frac{v_2 - v_1}{v_1} \\100%

= \frac{p_1}{p_2} v_1 - v_1.100%

= \frac{\frac{1.2}{1.015} - 1}{1} . 100%

= Therefore % increase in velocity is 18.23 %

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A moving body has energy due to its motion. This energy is called
fgiga [73]

Answer:

kinetic energy is the answer

Explanation:

kinetic energy is movement

4 0
3 years ago
A pendulum clock gives correct time at 20°c how many sec/day will it gain or loose when the temperature fall to 5°c? cofficient
rewona [7]

Answer:

129.6 seconds

Explanation:

Given that :

α = 0.0002°c-1​

θ1 = 20°C

θ2 = 5°C

Time t = one day ; Converting to seconds ; number of seconds in a day ; (24 * 60 * 60) = 86400 seconds

Let dT= change in time

Using the relation :

dT = 0.5* α * dθ * t

dθ = (20 - 5) = 15°C

dT = 0.5 * 0.0002 * 15 * 86400

dT = 129.6 seconds

5 0
2 years ago
Explain the difference between an electrically charged and a neutral object
Stella [2.4K]

An electrically charged element is called an "ion". A neutral element is an atom.

7 0
3 years ago
If a roller coaster car had 40,000 J of gravitational potential energy when at rest on the top of a hill how much kinetic energy
Inessa [10]

Answer:

K.E = 30,000 J

Explanation:

Given,

The potential energy of the roller coaster car, P.E = 40000 J

The kinetic energy at height h/4, K.E = ?

According to the law of conservation of energy, the total energy of the system is conserved.

At height 'h', the total energy is,

                                    P.E = mgh

                                     K.E = 0

At height 'h/4', the total energy is

                                     P.E + K.E = mgh

                                     P.E = mgh/4

                                     K.E = 1/2 mv²

Therefore,

                                   mgh/4 + 1/2 mv² = mgh

                                    gh/4 + v²/2 = gh

Hence,

                                      v² = 3gh/2

Substituting in the K.E equation

                               K.E = 1/2 mv²

                                      = 1/2 m (3gh/2)

                                       = 3/4 mgh

                                        = 3/4 x 40000

                                         = 30000 J

Hence, the K.E of the roller coaster car is, K.E = 30000 J

6 0
3 years ago
Steel train rails are laid in 12.0-m-long segments placed end to end. The rails are laid on a winter day when their temperature
Yanka [14]

Answer:

a) Space = 6.05 x 10^{-3} m = 0.605 cm

b) Stress= -100.8 x 10^{6} Pa

Explanation:

<em>1) Data Given</em>

L = 12 m , T_i = -9 C \degree, T_f = 33 C \degree

<em>2) Calculate the space using Linear thermal expansion formula</em>

We need to use Linear thermal expansion formula since the space created would be a change on 1 dimension, the increase of the temperature will increase the length of the steel.  The formula is given by:

\Delta L = L_i \alpha_{steel} \Delta T

We have everything except the \alpha_{steel} , so we look for this on a book and we find that \alpha_{steel} = 1.2 x 10^{-5} C^{-1}, so we can replace.

\Delta L = 12 m (1.2 x 10^{-5} C^{-1}) (33 C \degree -(-9 C \degree)) = 12 m (1.2 x 10^{-5} C^{-1}) 42 C \degree =6.048 x 10^{-3} m = 0.6048cm

<em>3) Calculate the stress of the steel </em>

The Stress is the ratio of applied force F to a cross section area - defined as

\sigma = \frac{F_n}{A}

Since we don't have the force and the Area, we need to look for another way to find the stress.

For this we can use the concept called Young's Modulus, defined as : "the mechanical property that measures the stiffness of a solid material", and the formula for this is given by:

Y =\frac{F L}{A \Delta L} (1)

Solving \frac{F}{A} from the previous formula we have this:

\frac{F}{A}  = (Y  Δ L)/L  (2)

From the <em>Linear thermal expansion formula</em> we can solve like this

\frac{\Delta L}{L} =  α  ΔT  (3)

And replacing equation (3) into equation (2) we have:

\frac{F}{A}  = Y α ΔT (4)

We have that the Young's Modulus for the steel is 20x10^{10} Pa, so replacing into equation (4)

\frac{F}{A} = 20x10^{10} Pa (1.2x10^-5 C^-1) (42C) = 100.8 *10^{6} Pa  

That represent the absolute value for the Stress, the sign on this case would be negative since there is a compression.

3 0
3 years ago
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