To solve this problem we will apply the considerations of equilibrium on a body, we will decompose the tensions into their respective components and apply the sum of forces and solving equations for the given system.
According to the graph, the sum of the horizontal components would be
The sum of the vertical components is
Therefore the net force on the new vine is 366.2N
Answer:
The ability to react to a certain stimulus with a speedy and effective manner
Explanation:
Answer:
Explanation:
Let the mass of bullet is m, initial velocity of bullet is vi and c be the specific heat of the bullet.
Kinetic energy, K = 1/2 mvi^2
According to the question, 50% of the kinetic energy is equal to the heat energy absorbed by the bullet.
50% of K = mass of bullet x specific heat x rise in temperature
1/4 mvi^2 = m x c x ΔT
Answer:
Speed of the wreckage = 49.29 km/hr
Explanation:
This question is solved simply by using the conservation of momentum law.
The momentum of the three moving bodies are calculated below:
Momentum of Car 1 : 1100 * 55 = 60500 kg.km/hr
Momentum of Truck : 480 * 37 = 17760 kg.km/hr
Momentum of Car 2 : 1300 * 49 = 63700 kg.km/hr
Total mass of all three vehicles: 1100 + 480 + 1300 = 2880 kg
The final momentum equals the initial momentum if it is conserved. Thus we have the following equation:
Final Momentum = Initial Momentum
Final Velocity * Total mass = Momentum of all three vehicles combined
Final Velocity * 2880 = 60500 + 17760 + 63700
Final Velocity = 49.29 km/hr
Complete question:
Seat belts and air bags save lives by reducing the forces exerted on the driver and passengers in an automobile collision. Cars are designed with a "crumple zone" in the front of the car. In the event of an impact, the passenger compartment decelerates over a distance of about 1 m as the front of the car crumples. An occupant restrained by seat belts and air bags decelerates with the car. In contrast, a passenger not wearing a seat belt or using an air bag decelerates over a distance of 5mm.
(a) A 60 kg person is in a head-on collision. The car's speed at impact is 15 m/s . Estimate the net force on the person if he or she is wearing a seat belt and if the air bag deploys.
Answer:
The net force on the person as the air bad deploys is -6750 N backwards
Explanation:
Given;
mass of the passenger, m = 60 kg
velocity of the car at impact, u = 15 m/s
final velocity of the car after impact, v = 0
distance moved as the front of the car crumples, s = 1 m
First, calculate the acceleration of the car at impact;
v² = u² + 2as
0² = 15² + (2 x 1)a
0 = 225 + 2a
2a = -225
a = -225 / 2
a = -112.5 m/s²
The net force on the person;
F = ma
F = 60 (-112.5)
F = -6750 N backwards
Therefore, the net force on the person as the air bad deploys is -6750 N backwards
