Answer:4.0*10^5 joules
Explanation:
Brainliest if correct Question 8 of 10
2 answers:
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Answer:
They will not stop at same elevation
for v=10m/2 => h=5.1m
for v=20m/2 => h=20.4m
Explanation:
If we neglect the effects of friction in the calculations the energy if the system must be conserved. The car energy can be described as a combination of kinetic energy and potential energy:
The potential energy is due to the gravitational forces and can be describes as:
Where g is the gravitation acceleration, m the mass of the car, and h the elevation. This elevation is a relative quantity and any point of reference will do the work, in this case we will consider the base of the hill as h=0.
The kinetic energy is related to the velocity of the car as:
As the energy must be constant E will be always constant, replacing the expressions for kinetic and potenctial energy:
In the base of the hill we have h=0:
When the car stops moving we have v=0:
This two must be equal:
solving for h:
Lets solve for the two cases:
for v=10m/2 => h=5.1m
for v=20m/2 => h=20.4m
As you can see, when the velocity is the double the height it reaches goes to four times the former one.
(a) -15.2 cm
We can solve the problem by using the lens equation:
where
f = -22.8 cm is the focal length of the lens (negative because it is a diverging lens)
p = 45.6 cm is the distance of the object from the lens
q is the distance of the image from the lens
Solving the equation for q, we find the position of the image:
and the negative sign means that the image is virtual.
(b) -11.4 cm
In this case, the distance of the object from the lens is
p = 22.8 cm
Substituting into the lens equation, we can find the new image distance, q:
and the negative sign means that the image is virtual.
(c) -7.6 cm
In this case, the distance of the object from the lens is
p = 11.4 cm
Substituting into the lens equation, we can find the new image distance, q:
and again, the negative sign means that the image is virtual.