A 15.0 kilogram cart initially traveling at 2.0 meters per second east accelerates uniformly at 0.75 meter per second squared ea
1 answer:
Answer:
Explanation:
Since this is not parabolic motion, it is one-dimensional motion. Very simple. What we are given is
mass: 15.0 kg
initial velocity: 2.0 m/s
acceleration: .75 m/s/s
time: 6.0 seconds
Since we are looking for final velocity, the equation we need for this is
v = v0 + at that says final velocity is equal to the initial velocity plus the acceleration of the object times how long it travels. We don't have a need for the mass here at all.
Notice that one of the seconds labels to the right of the plus sign cancel out, leaving us with like units...which we HAVE to have if we want to add.
Simplifying a bit gives us
v = 2.0 m/s + 4.5 m/s so
v = 6.5 m/s
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Answer:
V = 0.714m/s
Explanation:
Full solution calculation can be found in the attachment below.
From the principle of conservation of linear momentum, the sum of momentum before collision equals the sum of momentum after collision.
Before collision only the train had momentum. After the collision the train and the boxcars stick together and move as one body. The initial momentum of the train is now shared with the boxcars as they move together as one body. The both move with a common velocity v.
See the attachment below for the solution calculation.
Answer:
The displacement of the spring due to weight is 0.043 m
Explanation:
Given :
Mass Kg
Spring constant
According to the hooke's law,
Where force,
displacement
Here,
(
)
N
Now for finding displacement,
Here minus sign only represent the direction so we take magnitude of it.
m
Therefore, the displacement of the spring due to weight is 0.043 m
From the law of the lever:
<span>mechanical advantage= input arm : output arm
input arm- a
output arm-b
</span>
<span>Input arm is equal 4,8m</span>
<span>mechanical advantage= input arm : output arm
input arm- a
output arm-b
</span>
<span>Input arm is equal 4,8m</span>