1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Kazeer [188]
3 years ago
9

PLEASE HELP

Physics
2 answers:
nexus9112 [7]3 years ago
7 0

Answer:

hold up nvm Reaction with oxygen

Explanation:

Ymorist [56]3 years ago
6 0

Answer:

The correct answer is C) Solubility

Explanation:

You might be interested in
A 65.0 kg skier is moving at 6.85 m/s on a frictionless, horizontal snow-covered plateau when she encounters a rough patch 4.00
marusya05 [52]

Answer:

v = 4.58 m/s

Explanation:

In order to calculate the speed of the skier when she gets the bottom of the hill, you have to calculate the speed of the skier when she crosses the rough patch.

To calculate the velocity at the final of the rough patch you take into account that the work done by the friction surface is equal to the change in the kinetic energy of the skier:

W_f=\Delta K\\\\-N\mu_kd=\frac{1}{2}mv^2-\frac{1}{2}mv_o^2=\frac{1}{2}m(v^2-v_o^2)        (1)

Where the minus sign means that the work is against the motion of the skier.

Wf: friction force

m: mass of the skier = 65.0kg

N: normal force = mg

g: gravitational acceleration = 9.8m/s^2

d: distance of the rough patch = 4.00m

v: speed at the end of the rough patch = ?

vo: initial speed of the skier = 6.85m/s

μk: coefficient of kinetic friction = 0.330

You replace the expression for the normal force in the equation (1), and solve for v:

-mg\mu_kd=\frac{1}{2}m(v^2-v_o^2)\\\\-g\mu_kd=\frac{1}{2}(v^2-v_o^2)\\\\v=\sqrt{-2g\mu_kd+v_o^2}\\\\v=\sqrt{-2(9.8m/s^2)(0.330)(4.00m)+(6.85m/s)^2}=8.53\frac{m}{s}=4.58\frac{m}{s}

Then, the speed fot he skier at the bottom of the hill is 4.58m/s

3 0
4 years ago
Wat is matter made of?
Alex Ar [27]

Matter is made of the particles are called atoms!

hope this helps!

3 0
3 years ago
You are travelling by skateboard at 3.0 m/s and start to accelerate. If you
vovangra [49]

Answer: 8m/s

Explanation:

Vs= 3 m/s

Vf=?

a=0.5m/s²

t=10s

-----------

a=Vf-Vs/t

at=Vf-Vs

0.5*10s=Vf-Vs

5m/s=Vf-3m/s

5m/s+3m/s=Vf

Vf=8m/s

6 0
3 years ago
Write 200m and 2 ×10^4m in km<br><br><br>write 5000ms and 5×10^7ms in seconds
WINSTONCH [101]

Answer:

a) 20.2 kilometers

b)50 005 seconds

Explanation:

5 0
3 years ago
You would like a pendulum that swings back and forth once every 2 seconds, but the one you have swings once every 1.9 seconds. W
patriot [66]

Your pendulum does a complete swing in 1.9 seconds.  You want to SLOW IT DOWN so it takes 2.0 seconds.

Longer pendulums swing slower.

You need to <em>make your pendulum slightly longer</em>.

If your pendulum is hanging by a thread or a thin string, then its speed doesn't depend at all on the weight at the bottom.  You can add weight or cut some off, and it won't change the speed a bit.  

6 0
4 years ago
Other questions:
  • 18. Two spaceships are traveling in the same direction. With respect to an inertial frame of reference, spaceship A has a speed
    11·1 answer
  • What is the quantum distance from planet Nebula to Planet earth?
    5·1 answer
  • In any energy conversion, some of the energy is lost to the environment as
    8·1 answer
  • White bunnies are a common sight on farms and in pet stores. Why are these domestic white rabbits uncommon in the wild?
    8·2 answers
  • Q1. What is the frequency of rotation of 1000 loop coil of area 20cm2 in a magnetic field of 5T to
    10·1 answer
  • A 0.2 kg block sliding on a horizontal table slows down from 25 m/s to 20 m/s. How much energy does the block lose due to fricti
    6·2 answers
  • If two equal forces act on an object in opposite directions, what is the net
    6·1 answer
  • A ball of mass m is hung from the end of a vertical, unstretched spring of negligible mass and force constant k, then released f
    13·1 answer
  • Equation for distance
    5·1 answer
  • There are initially No nuclei in a radioactive source. After a time interval of three half-lives, what is the number of nuclei t
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!