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3 years ago

PLEASE HELP

Physics

2 answers:

nexus9112 [7]3 years ago

7 0

Answer:

hold up nvm Reaction with oxygen

Explanation:

Ymorist [56]3 years ago

6 0

Answer:

The correct answer is C) Solubility

Explanation:

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Two closed organ pipe gives 4 beats when sounded together at 5°C. Calculate the number of beats in 35°C

Gre4nikov [31]

Answer:

The number of beats is 10.58 in 35°C.

Explanation:

The beat frequency is given by : f₁-f₂

At 5°C, f₁-f₂ = 4

We need to find the number of beats in 35°C.

The frequency in a standing wave is proportional to $\sqrt T$ .

So,

$\dfrac{f_1-f_2}{f_1'-f_2'}=\dfrac{\sqrt {T}}{\sqrt{T'}}\\\\f_1'-f_2'=(f_1-f_2)\times \dfrac{\sqrt{T'}}{\sqrt{T}}\\\\f_1'-f_2'=4\times \dfrac{\sqrt{35}}{\sqrt{5}}\\\\f_1'-f_2'=10.58$

So, the number of beats is 10.58 in 35°C.

7 0

3 years ago

Corresponding propositions cannot both be false.

Fofino [41]

Answer:

Suggestions are opposite when the two of them can't be valid. An A suggestion, e.g., "all giraffes have long necks" can't be valid simultaneously as the comparing E recommendation: "no giraffes have long necks." Note, in any case, that relating An and E suggestions, while opposite, are not conflicting.

Explanation:

8 0

4 years ago

Read 2 more answers

What is the approximate size of the smallest object on the Earth that astronauts can resolve by eye when they are orbiting 250 k

sesenic [268]

Answer:

the approximate size of the smallest object on the Earth that astronauts can resolve by eye when they are orbiting 250 km above the Earth is y = 31.495 m

Explanation:

Using Rayleigh criterion for the limiting angle of resolution of an eye

$\theta = \frac{1.22\lambda }{D } \\ \\ \theta = \frac{1.22*506 *10^{-9} }{4.90*10^{-3}m}$

$\theta = 1.2598*10^{-4}$ rad

$\theta = 125.98*10^{-6} \ rad$

Thus; the separation between the two sources is expressed as:

$\theta = \frac{y}{L} \\ \\ y = L \theta \\ \\ y = (250*10^3 )(125.98*10^{-6} \ rad) \\ \\ y = 31.495 \ m$

Thus; the approximate size of the smallest object on the Earth that astronauts can resolve by eye when they are orbiting 250 km above the Earth is y = 31.495 m

8 0

3 years ago

A 3.0 kg object is loaded into a toy spring gun, and the spring has a spring constant 750N/m. The object compresses the spring b

kiruha [24]

Answer:

Explanation:

mass of object, m = 3 kg

spring constant, K = 750 n/m

compression, x = 8 cm = 0.08 m

angle of gun, θ = 30°

(a) As the ball is launched, it has some velocity due to the compression in the spring, so it has some kinetic energy.

(b) Let v be th evelocity of ball at the tim eof launch.

by using the conservation of energy

1/2 Kx² = 1/2 mv²

750 x 0.08 x 0.08 = 3 x v²

v = 1.265 m/s

By use of the formula of maximum height

$h = \frac{v^{2}Sin^{2}\theta}{2g}$

$h = \frac{1.265^{2}Sin^{2}30}{2\times 9.8}$

h = 0.02 m

h = 2 cm

4 0

3 years ago

An airplane flies 12 m/s due north with a velocity of 35.11 m/s. how far east does it fly?

goblinko [34]

The plane's velocity of 35.11 m/s is actually due in a north-eastward direction. The 12 m/s velocity is the vertical component of the plane's velocity, hence it is pointing northwards. We will use the formula:

Vy = Vsin∅

To determine the angle ∅ at which the plane is flying. This is:

12 = 35.11 * sin∅
∅ = 20.0 degrees

The eastward velocity is:

Vx = Vcos∅
Vx = 35.11 * cos(20)
Vx = 33.0 m/s

The plane's eastward velocity is 33.0 m/s

3 0

3 years ago

Read 2 more answers