Answer:
Both cars convert more kinetic energy to thermal energy.
Explanation:
Given that,
Two cars come to a stop from the same initial speed, one braking gently and the other braking hard.
We know that,
The conservation of energy :
The energy of the system is always constant.
The energy can be change one form to another form.
So, we can say that when both cars come to a stop from the same speed, one braking softly and the other braking strongly then both cars convert more kinetic energy to thermal energy.
Hence, Both cars convert more kinetic energy to thermal energy.
Answer:
1066.67 m
Explanation:
Given:
v₀ = 96 km/h = 26.67 m/s
v = 48 km/h = 13.33 m/s
Δx = 800 m
Find: a
v² = v₀² + 2aΔx
(13.33 m/s)² = (26.67 m/s)² + 2a (800 m)
a = -0.333 m/s²
Given:
v₀ = 26.67 m/s
v = 0 m/s
a = -0.333 m/s²
Find: Δx
v² = v₀² + 2aΔx
(0 m/s)² = (26.67 m/s)² + 2 (-0.333 m/s²) Δx
Δx = 1066.67 m
Round as needed.
Constructive interference will occur, which means the waves will combine.
In destructive inference, the waves cancel each other out.
Hope this helps :)
Answer:
The volume of water that was in the kettle is 1170 
Explanation:
Given:
Power, P = 2.0 kW = 2000 W, Mass of stainless steel, 
= 710 g = 0.71 kg at temperature of 
Part A:
If it takes time, t = 3.5 minutes to reach boiling point of water 
, then from conservation of energy,
Total energy supplied by the burner = Total heat gained by the water and the stainless steel to rise from to
i.e. Pt = 
(100 - 20 ) + 
(100 - 20 )
= 
= 1.17 kg
where = 4200 J/Kgk (specific heat capacity of water), = 450 J/Kgk (specific heat capacity of steel)
But volume of water in the the kettle, v = 
∴ v = 1170
Speed = d/t
d = 200, t = 10
200/10 = 20
Solution: 20 m/s
