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2 years ago

What causes moon phases, rotation or revolution

Physics

1 answer:

pav-90 [236]2 years ago

7 0

Answer:

The Moon's monthly

cycle of phases

results from the

changing angle of

its illumination by the Sun.

Because its period of

revolution is the same as its

period of rotation, the Moon

always keeps the same face

toward Earth.

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There is little vertical air movement in the __ because of the cold, heavy air at the bottom of the layer.

pogonyaev

The correct answer is the Mesosphere. Mesosphere is the layer of the Earth's atmosphere that is directly above the stratopause and directly below the mesopause.

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3 years ago

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when a cup of hot chocolate cools from 90c to 80c which of the following is happening to the molecules of the liquid

Murljashka [212]

Answer:

I think that the liquids molecules are slowing down. Hope this helps!

Explanation:

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3 years ago

A bowling ball is pushed with a force of 22.0N and accerlates at 5.5 m/s square. What is the mass of the bowling ball

stealth61 [152]

Mass of bowling ball is 4.0kg (A)

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2 years ago

If the swimmer starts at rest, slides without friction, and descends through a vertical height of 2.41 m

AveGali [126]

Answer:

6.88 m/s

Explanation:

The Conservation of Energy states that:

Initial Kinetic Energy + Initial Potential Energy = Final Kinetic Energy + Final Potential Energy

So we can write

$mgh_{i}+\frac{1}{2}mv_{i} ^{2}=mgh_{f}+\frac{1}{2}mv_{f} ^{2}$

We can cancel the common factor of $m$ which leaves us with

$gh_{i}+\frac{1}{2}v_{i} ^{2}=gh_{f}+\frac{1}{2}v_{f} ^{2}$

Lets solve for $v_f$

$gh_{i}+\frac{v_{i} ^{2}}{2}=gh_{f}+\frac{v_{f} ^{2}}{2}$

Subtract $gh_f$ from both sides of the equation.

$gh_{i}+\frac{v_{i} ^{2}}{2}-gh_{f}=\frac{v_{f} ^{2}}{2}$

Multiply both sides of the equation by 2.

$2(gh_{i}+\frac{v_{i} ^{2}}{2}-gh_{f})={v_{f} ^{2}$

Simplify the left side.

Apply the distributive property.

$2(gh_{i})+2\frac{v_{i} ^{2}}{2}+2(-gh_{f})={v_{f} ^{2}$

Cancel the common factor of 2.

$2gh_{i}+v_{i} ^{2}-2gh_{f}={v_{f} ^{2}$

Take the square root of both sides of the equation to eliminate the exponent on the right side.

${v_{f}=\sqrt{2gh_{i}+v_{i} ^{2}-2gh_{f}}$

We are given $g,v_{i},h_{i},h_{f}$ .

We can now solve for the final velocity.

${v_{f}=\sqrt{(2*9.81*2.41)+(0^{2})-(2*9.81*0)$

Anything multiplied by 0 is 0.

${v_{f}=\sqrt{2*9.81*2.41$

${v_{f}=\sqrt{47.2842$

$v_f=6.88$

7 0

1 year ago

A trolley going down an inclined plane has an acceleration of 2cm/s^2 What will be its velocity

Snowcat [4.5K]

Answer:

$V_{f}$ = 6 cm/s

Explanation:

Given:

Acceleration = a = 2 cm/s²

Time = t = 3s

Initial Velocity = $V_{i}$ = 0 cm/s

Required:

Velocity = $V_{f}$ = ?

Formula:

a = $\frac{V_{f}-V_{i}}{t}$

Solution:

2 = $\frac{V_{f}-0}{3}$

=> $V_{f}$ = 2*3

=> $V_{f}$ = 6 cm/s

5 0

3 years ago