Consider
.. X = {1, 2, 3, 4}, x = 4
.. Y = {2, 3, 4, 5, 6}, y = 5, w = 3
The elements in X or Y (X ∪ Y) are {1, 2, 3, 4, 5, 6}, n = 6.
.. n = 6 = 4 + 5 - 3
Note that if we just add x and y, we count the common elements twice. In order to just count the common elements once, we need to subtract that count from the total of x and y.
selection B is appropriate.
Answer:
m=5 and p=4
Step-by-step explanation:
Answer: 2/5
Step-by-step explanation:
Number of cans of red paint = 3
Number of cans of blue paint = 5
Number of cans of green paint = 8
Number of cans of yellow paint = 4
Total number of cans of paint = 20
The probability that Eduardo will
choose a can of red paint or a can of blue will be:
= P(red) + P(blue)
= 3/20 + 5/20
= 8/20
= 2/5
The probability is 2/5.
