Answer:
The smallest sample size required to obtain the desired margin of error is 44.
Step-by-step explanation:
I think there was a small typing error, we have that 
is the standard deviation of these weighs.
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so 
Now, find the margin of error M as such
Which of these is the smallest approximate sample size required to obtain the desired margin of error?
This sample size is n.
n is found when 
So
Simplifying by 15
Rounding up
The smallest sample size required to obtain the desired margin of error is 44.
Answer:
x=7
Step-by-step explanation:
415 + d ≥ 500
I believe that's the inequality since they want to raise a minimum of $500 so that means it can be more than $500. Hope I helped.
If triangles PQR and STU are similar then PQ corresponds to ST and PR corresponds to SU. Therefore, PQ/ST=PR/SU
Considering that, PQ= 7-x, ST= 13-x, PR= x²+5 and SU= x² +20
therefore, (7-x)/(13-x)= (x²+5)/(x²+20)
cross multiplying,
7x² +140-x³+20x =13x²+65-x³-5x
combining the like terms,
6x² +15x -75=0
solving for x,
x = 5/2 or -5
<h3>Answer: B) 25 = 10 + w</h3>
