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k0ka [10]
2 years ago
9

Hey.........................

Mathematics
2 answers:
motikmotik2 years ago
8 0

Answer:

hi........................................

Nastasia [14]2 years ago
4 0

Answer:

yo.......................

Step-by-step explanation:

You might be interested in
What is the length of BC? Round to the nearest tenth.
emmasim [6.3K]

9514 1404 393

Answer:

  (c) 14.5 cm

Step-by-step explanation:

The relevant trig relation is ...

  Sin = Opposite/Hypotenuse

  sin(65°) = BC/BA

  BC = BA·sin(65°) ≈ (16 cm)·0.9063 ≈ 14.501 cm

  BC ≈ 14.5 cm

_____

<em>Additional comment</em>

As is often the case, a simple estimate is all that is needed to identify the correct answer choice.

You only need to know how the long side of a right triangle compares to the others. In an isosceles right triangle, both legs are √2/2 ≈ 0.71 times the hypotenuse. The long side of a right triangle will never be shorter than that. This means the long side must be greater than about 11.2, and cannot be greater than 16. There is only one answer choice in that range.

4 0
3 years ago
Question
Aleonysh [2.5K]

Answer:

\large \boxed{-40, \ 4, \ -4}

Step-by-step explanation:

f(x)=-9x+14

\sf Put \ x \ as \ 6.

f(6)=-9(6)+14

f(6)=-54+14

f(6)=-40

g(x)=-3x^2

\sf Put \ g(x) \ as \ -48.

-48=-3x^2

\displaystyle \frac{-48}{-3} =\frac{-3x^2 }{-3}

16=x^2

\sqrt{16} =\sqrt{x^2 }

x= \pm 4

6 0
3 years ago
Read 2 more answers
A man walks 10 km, then travels a certain distance by train and then by bus as far as twice by the train. If the whole journey i
Nostrana [21]

Answer:

The man traveled 20km by train.

Step-by-step explanation:

If x is the distance he traveled by train, you can write this equation to represent the situation:

10+x+2x=70

Then, you can simply solve for x:

10+3x=70\\3x=60\\x=20

The man traveled 20km by train.

10+(20)+2(20)=70\\10+20+40=70\\70=70

3 0
2 years ago
Find the sum of all positive integers less than 200 that are divisible by 7.
Troyanec [42]

Step-by-step explanation:

the positive integer numbers that are divisible by 7 are an arithmetic sequence by always adding 7 :

a1 = 7

a2 = a1 + 7 = 7+7 = 14

a3 = a2 + 7 = a1 + 7 + 7 = 7 + 2×7 = 21

...

an = a1 + (n-1)×7 = 7 + (n-1)×7 = n×7

the sum of an arithmetic sequence is

n/2 × (2a1 + (n - 1)×d)

with a1 being the first term (in our case 7).

d being the common difference from term to term (in our case 7).

how many terms (what is n) do we need to add ?

we need to find n, where the sequence reaches 200.

200 = n×7

n = 200/7 = 28.57142857...

so, with n = 29 we would get a number higher than 200.

so, n=28 gives us the last number divisible by 7 that is smaller than 200 (28×7 = 196).

the sum of all positive integers below 200 that are divisible by 7 is then

28/2 × (2×7 + 27×7) = 14 × 29×7 = 2,842

6 0
2 years ago
49.2532 rounded to 1 decimal place
erastova [34]
The answer is 49.3!
5 0
3 years ago
Read 2 more answers
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