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2 years ago

Please help!! There is a photo of my question

Mathematics

1 answer:

goldfiish [28.3K]2 years ago

6 0

Answer:

0.03A + 0.03B = 800

A + B = 20000

Step-by-step explanation:

Let one part A of the total money invested with 3% interest = $A

Therefore, other part B of the money invested with 5% interest = $B

Interest = Principal amount × Rate of interest × Duration of investment

If the duration is 1 year,

Interest = Principal amount × Rate of interest

Return on part A = A × 0.03

Return on part B = B × 0.05

Total return = $800

So the equations will be,

0.03A + 0.03B = 800 -------(1)

Since, total money invested = $20000

Equation will be,

A + B = 20000 -------(2)

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Nana76 [90]

Answer:

A. is incorrect. He has to divide 76 by 19, instead of subtracting 19 to 76.

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Step-by-step explanation:

Hi, Martin’s answer is incorrect.

A. He has to divide 76 by 19, instead of subtract 19 to 76.

The correct steps are:

19v = 76

Since 19 is multiplying the variable, to eliminate it we have to divide by 19.

v = 76/19

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3 years ago

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Evaluate the expression -2cd if a = -8 b = 2 c = -5 d = 6

Elza [17]

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2 years ago

Nonlinear Systems of Equations

zheka24 [161]

The square root and cube root identities are proved.

According to the statement

we have to find that the use of the square root identity (x − y)2 = x2 − 2xy + y2

And use of cube root identity a3 + b3 = (a + b)(a2 − ab + b2).

So, For this purpose, we know that the

A. Let us assume the two conditions.

So,

2x + 3y = 6 -(1)

4x + 7y = 8 -(2)

Here we use elimination method

So, Multiply 4 with (1) and 2 with (2)

8x + 12y = 24

8x + 14y = 16

Now eliminate x from these equations

-2y = 8

here y is -4.

and the x become

2x + 3y = 6

2x -12 = 6

2x = 18

x = 9.

B. For the use of identity $(x- y)^{2} = x^{2} - 2xy + y^{2}$

Let us assume a number 26 and 28 then fill it in the condition then

$(28- 26)^{2} = 28^{2} - 2(28)(26) + 26^{2}$

Then

$(28- 26)^{2} = 784 - 1456 + 676$

$(28- 26)^{2} = 4$

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The identity is

$a^{3} + b^{3} = (a + b)(a^{2} - ab + b^{2})$

Then let us assume the number 8 and 9 then

$a^{3} + b^{3} = (a + b)(a^{2} - ab + b^{2})$

$8^{3} + 9^{3} = (8 + 9)(8^{2} - 8*9 + 9^{2})$

$8^{3} + 9^{3} = (17)(64 - 72 + 81)$

$8^{3} + 9^{3} = (17)(73)$

$8^{3} + 9^{3} = (1241)$

Hence by this way we prove the square and cube root identities.

So, The square root and cube root identities are proved.

Learn more about square root and cube root here

brainly.com/question/661780

#SPJ1

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1 year ago