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3 years ago

Which statement describes the possible interaction(s) between two objects

Physics

1 answer:

Inessa [10]3 years ago

4 0

Answer:

C. Gravitational forces only cause objects to be attracted to each

other, and magnetic and electric forces can cause objects to

attract or repel each other.

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A truck is using a hook to tow a car whose mass is one quarter that of the truck. If the force exerted by the truck on the car i

RideAnS [48]

answer

6000 N

explanation

every force has an equal and opposite reaction force, so the force exerted by the truck on the car is the same as the force exerted by the car on truck

the force is 6000 N

8 0

4 years ago

Read 2 more answers

A giraffe, standing 6.00 m tall, bites a branch off a tree to chew on the leaves

Lemur [1.5K]

Answer:

1.11 s.

Explanation:

From the question given above, the following data were obtained:

Height (H) = 6 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =.?

The time taken for the branch to hit the ground can be obtained as follow:

H = ½gt²

6 = ½ × 9.8 × t²

6 = 4.9 × t²

Divide both side by 4.9

t² = 6/4.9

Take the square root of both side

t = √(6/4.9)

t = 1.11 s

Therefore, it will take 1.11 s for the branch to hit the ground.

6 0

3 years ago

What do we call the temperature at which a liquid changes to a solid

lara31 [8.8K]

Answer: melting point

Explanation:

7 0

3 years ago

A giant wall clock with diameter d rests vertically on the floor. The minute hand sticks out from the face of the clock, and its

Katyanochek1 [597]

Answer:

$d_{x}(t)=(D/2)cos(\frac{\pi}{30}*t)$

Explanation:

We can try writing the equation of the horizontal component of the length of the minute hand in terms of distance and the angle, that depends of time in this particular case.

The x-component of the length of the minute hand is:

$d_{x}(t)=dcos(\theta (t))$ (1)

d is the length of the minute hand (d=D/2)
D is the diameter of the clock
t is the time (min)

Now, using the angular kinematic equations we can express the angle in term of angular velocity and time. As we know, the minute hand moves with a constant angular velocity, so we can use this equation:

$\theta (t)=\omega *t$ (2)

Also we know, that the minute hand moves 90 degrees or π/2 rad in 15 min, so using the definition of angular velocity, we have:

$\omega=\frac{\Delta \theta}{\Delta t}=\frac{\theta_{f}-\theta_{i}}{t_{f}-t{i}}=\frac{\pi/2-0}{15-0}=\frac{\pi}{30}$

Now, let's put this value on (2)

$\theta (t)=\frac{\pi}{30}*t$

Finally the length x(t) of the shadow of the minute hand as a function of time t, will be:

$d_{x}(t)=(D/2)cos(\frac{\pi}{30}*t)$

I hope it helps you!

6 0

3 years ago

A thin, horizontal square copper plate has a length of 6.35cm and is charged with 2.56 × 108 electrons. If the electrons are uni

Strike441 [17]

This is either a trick question or a very hard one. In the first case: An electric field cannot occur inside a conductor (or by using the superposition principle you find out that at this point your electric fields cancel each other out)... Or you must use the laplace equation and proper boundary conditions to solve for the electrostatic potential

<span>Edit: Considering the center of mass of the plate is on the plate</span>

5 0

3 years ago