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Sonbull [250]
3 years ago
13

How does beam spreading affect the temperature on earth and the seasons

Physics
1 answer:
navik [9.2K]3 years ago
8 0
Get to school and learn boi
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If a car change the velocity from 36M/S to 28M/S with an acceleration of -2.0 M/S then how much time does it take for the vehicl
leonid [27]

The time it will take if a car change the velocity from 36m/s to 28m/s with an acceleration of -2.0m/s² is 4s.

<h3>How to calculate deceleration?</h3>

Deceleration is the amount by which a speed or velocity decreases (and so a scalar quantity or a vector quantity).

The deceleration of a body can be calculated using the following formula:

-a = (v - u)/t

Where;

  • -a = deceleration
  • v = final velocity
  • u = initial velocity
  • t = time in seconds

-2 = (28 - 36)/t

-2t = -8

t = 4s

Therefore, the time it will take if a car change the velocity from 36m/s to 28m/s with an acceleration of -2.0m/s² is 4s.

Learn more about deceleration at: brainly.com/question/4403243

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6 0
2 years ago
do clouds and wind appear to follow the same patterns? Can you find any patterns in the direction that they move?
aniked [119]
What scientists use to make models of the Earth's water cycle so they can<span> see how it is ... Where </span>does<span> the water that we use to meet our everyday needs come from? .... what </span>you<span> notice about the </span>patterns<span> the</span>winds<span> and </span>clouds follow<span>: </span>Do clouds and<span> ... </span>same patterns<span>? </span>Can you find any patterns in the direction that they move? Precipitation is a vital component of how water moves through Earth’s water cycle, connecting the ocean, land and atmosphere. Water evaporates from the surface of the land and oceans, rises and cools, condenses into rain or snow, and falls again to the surface as precipitation. The water falling on land collects in rivers and lakes, soil, and porous layers of rock, and much of it flows back into the oceans. The cycling of water in and out of the atmosphere is a significant aspect of the weather patterns on Earth. so that will be probs the best i can do
6 0
3 years ago
Tapping into this energy source could provide at least 10 times the energy that can be obtained from the nation’s known coal res
ipn [44]

Tapping means the maximum use of the energy by the people.

<h3>What is energy?</h3>

The energy is the ability to do work.

The energy that can be tapped is solar energy. There are many ways developed to tap the solar energy and make the best use of it by solar plant, water heating, cooking, etc.

Thus, tapping means the maximum use of the energy by the people.

Learn more about tapping.

brainly.com/question/18623323

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6 0
2 years ago
A 100-W (watt) light bulb has resistance R=143Ω (ohms) when attached to household current, where voltage varies as V=V0sin(2πft)
Phantasy [73]

Complete Question

A 100-W (watt) light bulb has resistance R=143Ω (ohms) when attached to household current, where voltage varies as V=V0sin(2πft), where V0=110 V, f=60 Hz. The power supplied to the bulb is P=V2R J/s (joules per second) and the total energy expended over a time period [0,T] (in seconds) is U  =  \int\limits^T_0 {P(t)} \, dt

Compute U if the bulb remains on for 5h

Answer:

The value is  U  =  7.563 *10^{5} \  J

Explanation:

From the question we are told that

   The power rating of the bulb is P  =  100 \  W

   The resistance is   R =  143 \ \Omega

   The  voltage is  V  =  V_o  sin [2 \pi ft]

   The  energy expanded is U  =  \int\limits^T_0 {P(t)} \, dt

   The  voltage  V_o  =  110 \  V

   The frequency is  f =  60 \  Hz

    The  time considered is  t =  5 \  h  =  18000 \  s

Generally power is mathematically represented as

             P =  \frac{V^2}{ R}

=>          P =  \frac{( 110  sin [2 \pi * 60t])^2}{ 144}

=>           P =  \frac{ 110^2 [ sin [120 \pi t])^2}{ 144}

So  

     U  =  \int\limits^T_0 { \frac{ 110^2*  [sin [120 \pi t])^2}{ 144}} \, dt

=>  U  =  \frac{110^2}{144} \int\limits^T_0 { (   sin^2 [120 \pi t]} \, dt

=>  U =  \frac{110^2}{144} \int\limits^T_0 { \frac{1 - cos 2 (120\pi t)}{2} } \, dt

=>  U =  \frac{110^2}{144} \int\limits^T_0 { \frac{1 - cos 240 \pi t)}{2} } \, dt

=>  U =  \frac{110^2}{144} [\frac{t}{2}  - [\frac{1}{2} *  \frac{sin(240 \pi t)}{240 \pi} ] ]\left  | T} \atop {0}} \right.

=>  U =  \frac{110^2}{144} [\frac{t}{2}  - [\frac{1}{2} *  \frac{sin(240 \pi t)}{240 \pi} ] ]\left  | 18000} \atop {0}} \right.

U =  \frac{110^2}{144} [\frac{18000}{2}  - [\frac{1}{2} *  \frac{sin(240 \pi (18000))}{240 \pi} ] ]

=>   U  =  7.563 *10^{5} \  J

7 0
3 years ago
Reread the introduction section of this activity. Write a brief conclusion for this activity
ki77a [65]

Answer:

can you write proper

Explanation:

I don't understand

4 0
3 years ago
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