Answer:
The temperature would be reduced by half
Explanation:
Charles' Law => V ∝ T => V = kT => k = V/T
For two sets of T vs V conditions, the system constant (k) remains unchanged and k₁ = k₂ => V₁/T₁ = V₂/T₂.
Therefore, if V₁ is reduced to 1/2V₁ = V₂ => V₁/T₁ = 1/2V₁/T₂ => V₁/T₁ = V₁/2T₂
and solving for T₂ => 1/T₁ = 1/2T₂ => 2T₂ = T₁ => T₂ = 1/2T₁
∴ The initial temperature (T₁) would be reduced by half or, T₂ = 1/2T₁
