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3 years ago

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It has been estimated that 8.0 x 10^4 tons of gold (Au) have been mined. Assume gold costs $1350 per troy ounce. What is the tot

al worth of this quantity of gold? (1 troy ounce =31.103 g)

1 answer:

vodomira [7]3 years ago

4 0

Answer:

$\$ 3.14\times 10^{12}$ is the total worth of this quantity of gold.

Explanation:

Estimated mass of gold =M = $8.0\times 10^4 tons$

1 troy ounce = 31.103 g

1 ton = 907185 g

1 g= $\frac{1}{907185} ton$

$31.103 g= 31.103\times \frac{1}{907185} ton=3.4285\times 10^{-5} ton$

1 troy ounce = $3.4285\times 10^{-5}ton$

$1 ton = \frac{1}{3.4285\times 10^{-5}}\text{troy ounce}$

$=2.9167\times 10^4 \text{troy ounce}$

M = $8.0\times 10^4 tons=8.0\times 10^4\times 2.9167\times 10^4 \text{troy ounce}$

M = $2.333\times 10^{9}$ troy ounces

Cost of 1 troy ounce gold = $1350

Cost of $2.333\times 10^{9}$ troy ounces of gold =

$\$1350\times 2.333\times 10^{9} =\$ 3.14\times 10^{12}$

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Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

Rules for the balanced chemical equation in acidic solution are :

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Now balance the main atoms in the reaction.

Now balance the hydrogen and oxygen atoms on both the sides of the reaction.

If the oxygen atoms are not balanced on both the sides then adding water molecules at that side where the less number of oxygen are present.

If the hydrogen atoms are not balanced on both the sides then adding hydrogen ion $(H^+)$ at that side where the less number of hydrogen are present.

Now balance the charge.

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