Answer:
The balloon filled with Helium will effuse more quickly.
Explanation:
Step 1: Data given
Balloon 1: Has a volume 4.3L , a pressure of 1.68 atm and is filled with 1.21g of Helium
Balloon 2: Has also a volume of 4.3 L and a pressure of 1.68 atm but is filled with 39.63 grams of Xenon
Molar mass of He = 4g/mol
Molar mass of Xe = 131.3 g/mol
Since He is lighter than Xe, the effusion rate for He will be larger than that for Xe, which means the time of effusion for He will be smaller than that for Xe.
The balloon filled with Helium will effuse more quickly.
Answer:
See explanation below
Explanation:
In this case, we are having a reaction between an anion and alkyl halide. The carbon 1 of the anion will act as nucleophile and will attack the electrophile, which is 5 carbon chain with the bromine in the third carbon.
Now, the nucleophyle is an alkyne of 3 carbon. According to the description, it should be:
CH₃ - C ≡ C⁻
And the alkyl halide is:
CH₃ - CH₂ CH(Br) - CH₂ - CH₃
And the final product after the reaction would be the following:
CH₃ - C ≡ C - CH - (CH₂CH₃)₂
However, in the attached picture you can see this better and the mechanism of reaction.
Hope this helps