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Law Incorporation [45]
2 years ago
11

Match the special cases of each gas law with its description. A law may be used more than once. In the equations, K is a constan

t.
A. Boyle's law
B. Charles's law
C. Avogadro's law
D. Dalton's law

____ P1 V1 = P2 V2
____ V/T = k
____ V1 / T1 = V2 / T2
____ V = kn
____ PV = k
____ Ptotal = P1 + P2 + P3 + .​
Chemistry
1 answer:
Reptile [31]2 years ago
8 0

Answer:

A - P1V1 = P2 V2

B - V/T = K

B - V1 / T1 = V2 / T2

C - V = kn

A - PV = k

D - P total = P1 + P2 + P3 + .

Explanation:

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Which of these particles are lost in the oxidation process ?
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The answer is electrons !. Hope it helps !! :)
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List 2 things that about Velocity and Speed that are Different and two that are the same.
frozen [14]
Hey there!
Speed and velocity both:
1) Measure how fast something is moving
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Different because:
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8 0
3 years ago
Calculate the missing variables in each experiment below using Avogadro’s law.
blagie [28]

Answer:

The answer to your question is: letter c

Explanation:

Data

V1 = 612 ml    n1 = 9.11 mol

V2 = 123 ml    n2 = ?

Formula

                               \frac{V1}{n1}  =  \frac{V2}{n2}

                                         n2 = \frac{n1V2}{V1}

                                         n2 = \frac{(9.11)((123)}{(612)}

                                                n2 = 1.83 mol                                                

5 0
2 years ago
A 7.00-mL portion of 8.00 M stock solution is to be diluted to 0.800 M. What will be the final volume after dilution? Enter your
amm1812

Explanation:

The number of moles of solute present in liter of solution is defined as molarity.

Mathematically,         Molarity = \frac{\text{no. of moles}}{\text{Volume in liter}}

Also, when number of moles are equal in a solution then the formula will be as follows.

                     M_{1} \times V_{1} = M_{2} \times V_{2}

It is given that M_{1} is 8.00 M, V_{1} is 7.00 mL, and M_{2} is 0.80 M.

Hence, calculate the value of V_{2} using above formula as follows.

                    M_{1} \times V_{1} = M_{2} \times V_{2}

                 8.00 M \times 7.00 mL = 0.80 M \times V_{2}

                      V_{2} = \frac{56 M. mL}{0.80 M}

                                  = 70 ml

Thus, we can conclude that the volume after dilution is 70 ml.

7 0
2 years ago
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