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3 years ago

6. How is the law of conservation of mass shown by a balanced chemical equation?

Chemistry

1 answer:

tigry1 [53]3 years ago

6 0

Answer:

Any balanced equation shows the law of <em>conservation</em><em> </em><em>of</em><em> </em>mass as the number of reactant used would be equal to the number of product formed

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A dark brown binary compound contains oxygen and a metal. It is 13.38% oxygen by mass. Heating it moderately drives off some of

Leto [7]

Answer:

a) Mass of O in compound A = 32.72 g

Mass of O in compound B = 21.26 g

Mass of O in compound C = 15.94 g

b) Compound A = MO2

Compound B = M3O4

Compound C = MO

c) M = Pb

Explanation:

Step 1: Data given

A binairy compound contains oxygen (O) and metal (M)

⇒ 13.38 % O

⇒ 100 - 13.38 = 86.62 % M

After heating we get another binairy compound

⇒ 9.334 % O

⇒ 100 - 9.334 = 90.666 % M

After heating we get another binairy compound

⇒ 7.168 % O

⇒ 100 - 7.168 = 92.832 % M

The first compound has an empirical formula of MO2

⇒ 1 mol M for 2 moles O

Step 2: Calculate amount of metal and oxygen in each

compound A: M = m1 *0.8662 O = m1 *0.1338

compound B: M = m2 *0.90666 O = m2 *0.09334

compound C: M = m3 *0.92832 O = m3 *0.07168

Step 3: Calculate mass of oxygen with 1.000 grams of M

Compound A: 1.000g * 0.1338 m1gO / 0.8662m1gMetal = 0.1545

Compound B: 1.000g * 0.09334 m2gO / 0.90666m2gMetal = 0.1029

Compound C: 1.000g * 0.07168 m3gO / 0.92832m3gMetal = 0.07721

Step 4:

1 mol MO2 has 1 mol M and 2 moles O

m1 = (mol O * 16)/0.1338 m1 = 239.2 grams

1 mol M = 0.8632*239.2 = 206.48

0.90666m2 = 206.48 ⇒ m2 = 227.74 g

0.92832m3 = 206.48 ⇒ m3 = 222.42 g

Step 5: Calculate mass of O

Mass of O in compound A = 239.2 - 206.48 = 32.72 g

Mass of O in compound B = 227.74 - 206.48 = 21.26 g

Mass of O in compound C = 222.42- 206.48 = 15.94 g

Step 6: Calculate moles

Moles of O in compound A ≈ 2

⇒ MO2

Moles of O in compound B = 21.26 / 16 ≈ 1.33

⇒ M3O4

Moles of O compound C = 15.94 /16 ≈ 1 moles

⇒ MO

Step 7: Calculate molar mass

The mass of 1 mol metal is 206.48 grams ⇒ molar mass ≈ 206.48 g/mol

The closest metal to this molar mass is lead (Pb)

6 0

3 years ago

0.350 mol of a solid was dissolved in 260 mL of water at 21.2 oC. After the solid had fully dissolved, the final temperature of

Fittoniya [83]

Answer: Heat of the solution = mass water × specific heat water × change in temperature

mass water = 260ml (1.00g/ml ) = 260g

specific heat of water = c(water) = 4.184J/ g°C

Heat change of water = final temperature - initial temperature

= 26.5 - 21.2

= 5.3 °C

H = 260 g ( 4.184J/g°C ) (5.3°C) = 5765J

Molar heat = $\frac{5765J}{0.350mol}$

= 16473J/mol

Explanation: finding molar heat requires first to look at specific heat of water and the change of water temperature

7 0

3 years ago

How many moles of KNO3 are in 500 mL of 2. 0 M KNO3? mol KNO3.

8090 [49]

The moles can be defined as the mass of the substance with respect to molar mass. The moles of potassium nitrate is 1 mol.

<h3>How to calculate moles of a substance?</h3>

The moles of a compound can be calculated from:

$\rm Moles=\dfrac{Mass}{Molar\;mass}$

The molarity can be defined as the moles of solute in a liter of solution.

The molarity can be expressed as:

$\rm Molarity=\dfrac{Moles\;\times\;1000}{Volume\;(mL)}$

The molarity of potassium nitrate solution is 2 M, and the volume is 500 mL.

The moles of potassium nitrate is given as:

$\rm 2\;M=\dfrac{Moles\;\times\;1000}{500\;mL}\\ Moles=\dfrac{2\;\times\;500}{1000}\;mol\\ Moles=1\;mol$

The moles of potassium nitrate in 2 M, 500 mL solution are 1 mol.

Learn more about moles, here:

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4 0

2 years ago

If you could help me that would be awesome

elixir [45]

There are 3 significant figures. Significant numbers are the numbers that build up your total number. 1-9 always count, 0 only counts if it’s after another number. For example: 0,901 has 3 significant numbers as does 0,910. 9,10 also has 3. 0,09 has just 1.

8 0

3 years ago

What force is the type of intermolecular force that would be present between molecules of Cl2 ?

KatRina [158]

Cl2 is nonpolar so it has to be only London dispersion force (LDF)

7 0

3 years ago

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