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const2013 [10]
3 years ago
9

What is the simplest formula of a compound if a sample of the compound contains 0.221 mol X, 0.442 mol Y, and 0.884 mol Z? chemP

adHelp XY2Z4 XY_2Z_4 Correct. How many moles of Z would be in a sample that contained 0.588 mol X? WebAssign will check your answer for the correct number of significant figures.
Chemistry
2 answers:
bezimeni [28]3 years ago
7 0

Answer:

The simplest formula of this compound is XY2Z4

We would have 2.352 moles of Z in a sample that contains 0.588 moles X

Explanation:

Step 1: Data given

A compound contains 3 elements

X = 0.221 mol

Y = 0.442 mol

Z = 0.884 mol

Step 2: Calculate the mol ratio

We divide by the smallest amount of moles

X = 0.221/0.221 = 1

Y = 0.442/0.221 = 2

Z = 0.884/0.221 = 4

The empirical formula is XY2Z4

This means for each 1 X atom we have 2 Y atoms and 4 Z atoms.

If we have 0.588 moles X this means we have 0.588*2 = 1.176 moles of Y

And 0.588 *4 = 1.176*2 = 2.352 moles of Z

The simplest formula of this compound is XY2Z4

We would have 2.352 moles of Z in a sample that contains 0.588 moles X

Gnoma [55]3 years ago
6 0

Answer:

XY₂Z₄

2.35 mol Z

Explanation:

A sample of the compound contains 0.221 mol X, 0.442 mol Y, and 0.884 mol Z. We can find the simplest formula (empirical formula) by <em>dividing all the numbers of moles by the smallest one</em>.

X: 0.221/0.221 = 1

Y: 0.442/0.221 = 2

Z: 0.884/0.221 = 4

The simplest formula is XY₂Z₄.

The molar ratio of X to Z is 1:4. The moles of Z in a sample that contained 0.588 moles of X is:

0.588 mol X × (4 mol Z/1 mol X) = 2.35 mol Z

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