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Ilya [14]
3 years ago
13

A baker sold 120 banana muffins and 60 blueberry muffins what was the ratio of banana muffins to blueberry muffin sold and

Mathematics
2 answers:
andrew-mc [135]3 years ago
8 0

Answer:

120:60 or :=to

Step-by-step explanation:

inessss [21]3 years ago
3 0

Answer:

the answer is 120 to 60

Step-by-step explanation:

it says "ratio of banana muffins to blueberry muffins" so just replace the word for the flavor of muffin and replace it with the number of muffins sold of that flavor

banana muffins : blueberry muffins

         120           :          60

PLZZZZ give brainlyest

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TV advertising agencies face increasing challenges in reaching audience members because viewing TV programs via digital streamin
choli [55]

Answer:

a) The 99% confidence interval would be given (0.523;0.577).

We are 99% confident that this interval contains the true population proportion.

b) n=\frac{0.55(1-0.55)}{(\frac{0.03}{2.58})^2}=1830.51  

And rounded up we have that n=1831

Step-by-step explanation:

Data given and notation  

n=2341 represent the random sample taken    

X represent the people that they have watched digitally streamed TV programming on some type of device

\hat p=0.55 estimated proportion of people that they have watched digitally streamed TV programming on some type of device  

\alpha=0.01 represent the significance level

Confidence =0.99 or 99%

z would represent the statistic for the confidence interval  

p= population proportion of people that they have watched digitally streamed TV programming on some type of device

The population proportion present the following distribution:

p \sim N (p, \sqrt{\frac{p(1-p)}{n}}

Part a) Confidence interval

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.58

And replacing into the confidence interval formula we got:

0.55 - 2.58 \sqrt{\frac{0.55(1-0.55)}{2341}}=0.523

0.55 + 2.58 \sqrt{\frac{0.55(1-0.55)}{2341}}=0.577

And the 99% confidence interval would be given (0.523;0.577).

We are 99% confident that this interval contains the true population proportion.

Part b) What sample size would be required for the width of a 99% CI to be at most 0.03 irrespective of the value of p??

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.03 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.55(1-0.55)}{(\frac{0.03}{2.58})^2}=1830.51  

And rounded up we have that n=1831

8 0
4 years ago
A gallon jug of milk is 5/6 full. After breakfast the jug is 1/12 full. Find the difference of the amounts before breakfast and
Oxana [17]
5/6=10/12

So 9/12 is the differemce
6 0
3 years ago
Read 2 more answers
408 rounded to the nearest tenth
andreev551 [17]
408 round to the nearest tenth: 410
3 0
3 years ago
What is an equation of the line that passes through the points (-4, -6)(−4,−6) and (4, 4)(4,4)?
Alik [6]

Answer:

y=5/4x-1

Step-by-step explanation:

5 0
3 years ago
Let f(x) = x ^ 2 and g(x) = x - 3 . Evaluate (g?f)(0).
nignag [31]

Answer:

g(f(0))=-3

Step-by-step explanation:

we have

f(x)=x^{2}

g(x)=x-3

we know that

(g o f)(x)=g(f(x))

substitute the variable x in the function g(x) by the function f(x)

so

g(f(x))=x^{2}-3

Evaluate g(f(0))

For x=0

g(f(0))=0^{2}-3

g(f(0))=-3

5 0
4 years ago
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