Answer:
The probability that a randomly selected student has a score between 350 and 550 = 0.5867
Step-by-step explanation:
Mean = 500
Standard deviation = 110
Let X be the score of student in a standardized test
The probability that a randomly selected student has a score between 350 and 550 =
=
= Putting
=
= 0.6736 - .0869 ( Using Z table )
= 0.5867
Answer:
2
a
b^
2
Step-by-step explanation:
1. Find the GCF for the numerical part 22
, 18
2. Find the GCF for the variable part a
^1
,
b^
3
,
a^
4
,b^
2
3. Multiply the values together
1. The common factors for 22, 18 are 1
,
2. The Greatest common factor is 2.
2. Next, find the common factors for the variable part: a
^1
,
b^
3
,
a^
4
,b^
2.
For a^1 it's a itself
For b^3 it's b*b*b
For a^4 it's a*a*a*a
For b^2 it's b*b
The common factors for the variables a
^1
,
b^
3
,
a^
4
,b^
2 are a
*b*b.
a*b*b is ab^2
3. Multiply the GCF of the numerical part 2
and the GCF of the variable part ab^2. That is 2
a
b^
2
3 409 653.453435 / (-45) =
-75770.076743
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