Question

A bus leaves a station traveling north at 70 kilometers per hour. Half an hour later a

Answer 1

Answer:

280 km

Step-by-step explanation:

Given that a bus, say $b_1$, leaves a station traveling north at speed of  70km/hour.

Half an hour later the second bus, say $b_2$,  leaves a station traveling north at speed of  70km/hour.

As, distance = speed x time,

so, the distance traveled by bus $b_1$ in 0.5 hours = 70 x 0.5 = 35 km.

Note that, both the buses are traveling in the same direction and when the second bus leaves the station, the first bus already covered a distance of 35 km.

Let the second bus took $t$ hours to meet the first bus and both the buses meet at a distance of $d$ km from the station.

The distance traveled by the first bus from the station, $d = 35 + 70t$ km

$\Rightarroe t= \frac {d-35}{70}\cdots(i)$

and the distance traveled by the second bus, $d = 80t$ km

$\Rightarrow t=\frac {d}{80}\cdots(ii)$

Now, equation the equation (i) and (ii), we have

$\frac {d-35}{70}=\frac {d}{80} \\\\\Rightarrow 8(d-35)=7d \\\\\Rightarrow 8d - 280 = 7d \\\\\Rightarrow 8d-7d=280 \\\\\Rightarrow d = 280 km$

Hence, both the bus will meet at a distance of 280 km from the station.