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gizmo_the_mogwai [7]
2 years ago
8

2. A ladder 16cm long weighs 420N and it's centre of gravity is 7m from one end.It is carried horizontally by two boys,each hold

ing it 1m from the ends. Show that the forces excreted by them are about 180N and 240N​
Physics
2 answers:
ipn [44]2 years ago
8 0

Answer:

well the answers are 180 and 240 obviously

Explanation:

Download pdf
MariettaO [177]2 years ago
7 0

Answer:

Explanation:

Givens

I take the ladder to be 16 m not 16 cm

The position of the boys.

Each boy is 1 m from the end

The mass of the ladder is 6m form one of the boys.

The fulcrum is at his shoulders,

The other boy is 14 feet from the fulcrum

Equation

420 *6 = 14 * x The boy nearest the fulcrum contributes nothing because he is 0 distance to the fulcrum.

Solution

420*6 = 14*x                Divide by 14

420*6/14 = 14x/14        Combine

30 *6 = x

x = 180

Answer

So the boy furthest from the fulcrum lifts 180 N of the 420N ladder

The other boy contributes 420 - 180 = 240 N

Both boys are represented by an arrow pointing upward.

The ladder's mass points down

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Musya8 [376]

Answer:

joule

Explanation:

7 0
3 years ago
It is determined that a certain light wave has a wavelength of 3.012 ×10−12 m. The light travels at 2.99 ×108 m/s. What is the f
horsena [70]

Answer:

Explanation:

velocity=frequency*wavelength

velocity = 2.99*10^8 m/s

frequency = ?

wavelength = 3.012*10^-12

2.99*10^8m/s = (f)(3.012*10^-12)

f=9.58*10^19 Hertz    

5 0
3 years ago
URGENT!!!
madreJ [45]

Answer:

f=6.97\times 10^{14}\ Hz

Explanation:

Given that,

Wavelength, \lambda=430\ nm=430\times 10^{-9}\ m

We need to find the frequency of the violet light.

We know that the relation between frequency and wavelength is given by :

f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{430\times 10^{-9}}\\\\f=6.97\times 10^{14}\ Hz

So, the frequency of violet light is 6.97\times 10^{14}\ Hz.

7 0
3 years ago
A ray of light passes from air into a block of clear plastic. How does the angle of incidence in the air compare to the angle of
andre [41]

Answer:

The angle of incidence is greater than the angle of refraction

Explanation:

Refraction occurs when a light wave passes through the boundary between two mediums.

When a ray of light is refracted, it changes speed and direction, according to Snell's Law:

n_1 sin \theta_1 = n_2 sin \theta_2

where :

n_1 is the index of refraction of the 1st medium

n_2 is the index of refraction of the 2nd medium

\theta_1 is the angle of incidence (the angle between the incident ray and the normal to the boundary)

\theta_2 is the angle of refraction (the angle between the refracted ray and the normal to the boundary)

In this problem, we have a ray of light passing from air into clear plastic. We have:

n_1=1.00 (index of refraction of air)

n_2=1.50 approx. (index of refraction in clear plastic)

Snell's Law can be rewritten as

sin \theta_2 =\frac{n_1}{n_2}sin \theta_1

And since n_2>n_1, we have

\frac{n_1}{n_2}

And so

\theta_2

Which means that

The angle of incidence is greater than the angle of refraction

6 0
3 years ago
Use the following half-life graph to answer the following question:
Temka [501]

Answer:

A 1.0 min

Explanation:

The half-life of a radioisotope is defined as the time it takes for the mass of the isotope to halve compared to the initial value.

From the graph in the problem, we see that the initial mass of the isotope at time t=0 is

m_0 = 50.0 g

The half-life of the isotope is the time it takes for half the mass of the sample to decay, so it is the time t at which the mass will be halved:

m'=\frac{50.0 g}{2}=25.0 g

We see that this occurs at t = 1.0 min, so the half-life of the isotope is exactly 1.0 min.

3 0
3 years ago
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