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gizmo_the_mogwai [7]

2 years ago

8

2. A ladder 16cm long weighs 420N and it's centre of gravity is 7m from one end.It is carried horizontally by two boys,each hold

ing it 1m from the ends. Show that the forces excreted by them are about 180N and 240N

2 answers:

ipn [44]2 years ago

8 0

Answer:

well the answers are 180 and 240 obviously

Explanation:

MariettaO [177]2 years ago

7 0

Answer:

Explanation:

Givens

I take the ladder to be 16 m not 16 cm

The position of the boys.

Each boy is 1 m from the end

The mass of the ladder is 6m form one of the boys.

The fulcrum is at his shoulders,

The other boy is 14 feet from the fulcrum

Equation

420 *6 = 14 * x The boy nearest the fulcrum contributes nothing because he is 0 distance to the fulcrum.

Solution

420*6 = 14*x Divide by 14

420*6/14 = 14x/14 Combine

30 *6 = x

x = 180

Answer

So the boy furthest from the fulcrum lifts 180 N of the 420N ladder

The other boy contributes 420 - 180 = 240 N

Both boys are represented by an arrow pointing upward.

The ladder's mass points down

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Explanation:

It is given that,

Mass of cardinal, $m_c=4.2\times 10^{-2}\ kg$

Mass of baseball, $m_b=0.146\ kg$

Both cardinal and baseball have same kinetic energy. We need to find the ratio of the cardinal's magnitude $p_c$ of momentum to the magnitude $p_c$ of the baseball's momentum.

$E_c=E_b$

Kinetic energy is given by, $E=\dfrac{p^2}{2m}$

$\dfrac{p_c^2}{2m_c}=\dfrac{p_b^2}{2m_b}$

$(\dfrac{p_c}{p_b})^2=\dfrac{m_c}{m_b}$

$\dfrac{p_c}{p_b}=\sqrt{\dfrac{m_c}{m_b}}$

$\dfrac{p_c}{p_b}=\sqrt{\dfrac{4.2\times 10^{-2}}{0.146}}$

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Answer:

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Explanation:

From the question we are told that

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Generally the total time taken is mathematically represented as

$t_t = 12 + 13$

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