Question

Car A leaves Santa Barbara at noon traveling south toward Los Angeles at 65 mph. At 1pm car B leaves Los Angeles traveling north toward Santa Barbara at 90 mph. The distance between the cars at noon was 100 miles. If car B does not get pulled over, how many minutes after car B leaves will they pass each other?

Answer 1

Answer:13.548 minutes

Explanation:

Given Speed of car A is 65 mph

Speed of car B is 90 mph

distance between cars at noon is 100 miles

as car A leaves ahead of car B thus car A travels extra for an hour which is equals to 65 miles

now the effective distance between cars is 35 mph

Now both car travels towards each other and meet after t hr

therefore

$t=\frac{x}{65}=\frac{35-x}{90}$

where x is distance covered by car A in time t

solving we get

$31x=35\times 13$

x=14.677 miles

35-x=20.323 miles

they will pass each other after

$t=\frac{14.677\times 60}{65}=13.54 minutes$