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cupoosta [38]
3 years ago
13

What is the third period element with 2 valence electrons

Chemistry
2 answers:
tia_tia [17]3 years ago
7 0

Answer:

<em>The</em><em> name of the element is magnesium </em>

I Hope this is right if not so sorry :)

aleksley [76]3 years ago
5 0

Answer:

Magnesium (symbol Mg)

Explanation:

Please Mark me brainliest

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This is how fluorine appears in the periodic table.
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A: the atomic number

C: the number of protons

D: the number of electrons

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The water cycle is also known as the _______ cycle?
valina [46]

Answer:

hydrological cycle

Explanation:

water cycle is also known as hydrological vycle

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Water is wet. true or false? Why?
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True water is wet because when something is wet in this case it's water it has water on it at a molecular level. Water molecules are bonded on top of each other so it's wet.

5 0
3 years ago
Hydrofluoric acid is used in the preparation of numerous pharmaceuticals (e.g., Prozac) and industrial materials (e.g., Teflon).
Natali [406]

Answer:

the equilibrium concentration of HF is 2.85 M

Option a) 2.85 M is the correct answer.

Explanation:

Given the data in the question;

     H₂         +      F₂      ⇄     2HF

I    1.69 M        1.69 M           0

C    -x                 -x               +2x

E    1.69-x         1.69-x          +2x

given that Kc = 115        

Kc = [ HF ]² / [H₂][F₂]

we substitute

115 = [ 2x ]² / [ 1.69-x  ][ 1.69-x ]

lets find the square root of both sides

10.7238 = 2x / [ 1.69-x  ]

10.7238[ 1.69-x  ] = 2x

18.123222 - 10.7238x = 2x

2x + 10.7238x = 18.123222

12.7238x = 18.123222

x = 18.123222 / 12.7238

x = 1.424356

Hence, equilibrium concentration of HF = 2x

that is;

HF = 2 × 1.424356

HF = 2.8487 ≈ 2.85 M

Therefore, the equilibrium concentration of HF is 2.85 M

Option a) 2.85 M is the correct answer.

5 0
3 years ago
What is the molarity of a solution prepared by dissolving 2.5 grams of LiNO3 in sufficient water to make 60.0 mL of solution?​
Murrr4er [49]

Answer: hope this helps

To make molar NaCl solutions of other concentrations dilute the mass of salt to 1000ml of solution as follows:

0.1M NaCl solution requires 0.1 x 58.44 g of NaCl = 5.844g.

0.5M NaCl solution requires 0.5 x 58.44 g of NaCl = 29.22g.

2M NaCl solution requires 2.0 x 58.44 g of NaCl = 116.88g.

Explanation:

6 0
4 years ago
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