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NeTakaya
3 years ago
9

How do we use chemistry in our everyday life?

Chemistry
1 answer:
Ludmilka [50]3 years ago
6 0

Answer:

we use the chemistry in our day to day life cooking and cleaning with chemical substance

Explanation:

You might be interested in
The properties of protons, neutrons and electrons.
Mashutka [201]
Properties of Protons: Positively charged particles in the nucleus (center) of an atom.

Properties of Neutrons: Neutral particles that have no electric charge in the nucleus. 

Properties of Electrons: Found outside the nucleus of the Atom.. 

I hope this helps! :)


7 0
3 years ago
to find the mass of 3.2 moles of calcium for carbonate which of the following is used to calculate the amount
natka813 [3]
I believe it to be g/mol of Calcium carbonate
because to finde mass...u must have grams(g) as units....
it is the only one that have g as units 

as for the first answer the avogadros number gives u the number of atoms in  one mole of calcium carbonate....
the second one is based on ... At s.t.p one mole of gas occupies 22.4 dm³⇒to find volume 
6 0
3 years ago
A 25 Ω resistor has a voltage drop of 12 V across it. Calculate the current flowing through the resistor
Yanka [14]

Answer:

0.48

Explanation:

i =  \frac{v}{r}

because we are looking for I which is current we say

I = 12÷25 which is 0.48.

4 0
3 years ago
g Gaseous methane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 0.96 g of methane
galben [10]

Answer: 2.64 g of carbon dioxide that could be produced by the chemical reaction.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} CH_4=\frac{0.96g}{16g/mol}=0.06moles

\text{Moles of} O_2=\frac{6.37}{32}=0.20moles

CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g)

According to stoichiometry :

1 mole of CH_4 require = 2 moles of O_2

Thus 0.06 moles of CH_4 will require=\frac{2}{1}\times 0.06=0.12moles  of O_2

Thus CH_4 is the limiting reagent as it limits the formation of product and O_2 is the excess reagent.

As 1 moles of CH_4 give = 1 mole of CO_2

Thus 0.06 moles of CH_4 give =\frac{1}{1}\times 0.06=0.06moles  of CO_2

Mass of CO_2=moles\times {\text {Molar mass}}=0.06moles\times 44g/mol=2.64g

Thus 2.64 g of carbon dioxide that could be produced by the chemical reaction.

7 0
4 years ago
How do the key results indicate
Lena [83]
The key results explain how you'll achieve a certain goal. They have to be quantitative, but always measurable in terms of their progress. This has to be considered when it comes to key results, because only results count for each milestone on the way to achieving the goal in question.
7 0
3 years ago
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