Answer:
C = (7 + 8) i + (5 - 1) j adding vectors
C = 15 i + 4 j
theta = arctan (4 / 15) = 14.9 deg
Note that this is the same as adding x and y components
Answer:
Turns ratio=108, Pin= 110.5 W, Current ratting= 920mA
Explanation:
Vp=120 V(rms)
Vs=13,000 V (rms)
Is = 8.50*10^-3 V(rms)
a.
secondary to primary turn ration:
Ns/Np=Vs/Vp
=
=
= 108
b.
Is=8.50 mA (rms)
As Vs= 13,000V (rms)
For ideal transformer
Pin=Pout______(1)
Pout= Is*Vs (put in equ 1)
Pi=Is*Vs
Pi=(8.50*10^-3)*(13,000) W
Pi=110.5 W
Power supplied will be 110.5 W.
c.
We have to find the current passing through primary circuit to find current rating of fuse in primary circuit.
For ideal case
Ip*Vp= Is*Vs
Ip=
Ip= (13000*8.5*10^-3)/120
Ip=920 mA
In primary circuit fuse current rating will be 920 mA.
Answer:
you can't
Explanation:
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The net force on the toy is 0 Newton.
The mass of the toy is 2 kg.
The force F₁ is the tension applied by one of the siblings on the toy is 8N.
Let us assume that the force applied by the other sibling is F₂, which is produced by the acceleration is 4m/s².
We know,
Force = Mass x acceleration
Putting values,
F₂ = 2 x 4
F₂ = 8N.
As we know that the forces are in opposite directions because the toy is being pulled by both the siblings in their respective directions which are opposite to each other.
Hence, the net force F is given by,
F = F₁ - F₂
F = 8-8
F 0N.
Hence, there is no net force on the toy.
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Basically its just an air like fluid with chemicals.... just like air it just goes as it pleases and fills space