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rewona [7]
4 years ago
14

you are moving fast on a skateboard when your wheel gets stuck in a crack on the sidewalk using the term inertia explain what ha

ppens
Physics
2 answers:
DENIUS [597]4 years ago
8 0

Answer:

Inertia is the tendency or ability of a body to remain at rest or in uniform motion along a straight line in the absence of any external force. It is the reluctance a body displays when agitated or encountered by an external.

By the law of inertia, an object will always remain in its position of rest or state of uniform motion along a straight line until it is engaged with an external force.

To put it in other words;

When an object is at rest, it will want to remain at rest. If it becomes engaged with an external force it will display some reluctance before it changes its mechanical state.

Similarly, when an object is in uniform motion, it will want to continue with the motion. If an external force then interrupts it, it will also display some reluctance. This reluctance is in the form of it wanting to continue its motion irrespective of the force.

So therefore if I am moving fast on a skateboard and suddenly I become interrupted with a force, by the law of inertia my tendency is to continue the motion and this makes me exhibit reluctance in responding to the force. This reluctance will then make me to topple over and fall off if there is nothing to quickly hold unto. The more massive I am, the greater the effect of the topple. The inertia of an object is proportional to its mass.

Leya [2.2K]4 years ago
5 0
When the wheels of the skateboard get stuck in the crack of the sidewalk, the riders inertia will continue forward and cause him to fall off/down.

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Whitepunk [10]

Answer: 96.138 J

Explanation:

Ep= mGh (on 1.2 m high)

Ep= 3.5kg*9.81*1.2

Ep1=41.202 J

Ep=mGh (on 4m high)

Ep=3.5*9.81*4

Ep2=137.34J

Ep= Ep2-Ep1

Ep=96.138J

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At which point is cool air circulating beneath warm air?
stepan [7]

Answer:

1

Explanation:

5 0
3 years ago
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Which of the following is not a means to reduce the rate of heat transfer by conduction through a wall?
DENIUS [597]
The correct answer is 3
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4 years ago
A 5 newton force and a 7 newton force act concurrently on a point. As the angle between the forces is increased from 0 to 180 th
Reika [66]

Answer:

The magnitude of the resultant decreases from A+B to A-B

Explanation:

The magnitude of the resultant of two vectors is given by

R=\sqrt{A^2 +B^2 +2AB cos \theta}

where

A is the magnitude of the first vector

B is the magnitude of the second vector

\theta is the angle between the directions of the two vectors

In the formula, A and B are constant, so the behaviour depends only on the function cos \theta. The value of cos \theta are:

- 1 (maximum) when the angle is 0, so the magnitude of the resultant in this case is

R=\sqrt{A^2 +B^2+2AB}=\sqrt{(A+B)^2}=A+B

- then it decreases, until it becomes 0 when the angle is 90 degrees, where the magnitude of the resultant is

R=\sqrt{A^2 +B^2+0}=\sqrt{A^2+B^2}

- then it becomes negative, and continues to decrease, until it reaches a value of -1 when the angle is 180 degrees, and the magnitude of the resultant is

R=\sqrt{A^2 +B^2-2AB}=\sqrt{(A-B)^2}=A-B


4 0
3 years ago
An alpha particle is a nucleus of Helium. It has twice the charge and four times the mass of the proton. When they were very far
Ierofanga [76]

Answer:

r = 2.65 \times 10^{-14} m

Explanation:

By energy conservation we know that initially when both are far apart from each other then in that case total electrostatic kinetic energy of two charges will convert into electrostatic potential energy of two charges

so we have

\frac{1}{2}m_1v_1^2 + \frac{1}{2}m_1v_2^2 = \frac{1}{2}(m_1 + m_2)v^2 + \frac{kq_1q_2}{r}

now we know that there is no external force on this system so momentum is conserved here

m_1v_1 - m_2v_2 = (m_1 + m_2) v

4mv - mv = 5m v_f

v_f = 0.6 v

now plug in all values in first equation

\frac{1}{2}4mv^2 + \frac{1}{2}mv^2 = \frac{1}{2}(4m + m)(0.6v)^2 + \frac{k(e)(2e)}{r}

1.6 mv^2 = \frac{2ke^2}{r}

r = \frac{2ke^2}{1.6 mv^2}

r = \frac{2(9\times 10^9)(1.6\times 10^{-19})^2}{1.6(1.67 \times 10^{-27})(8.5\times 10^{-3})^2(3\times 10^8)^2}

r = 2.65 \times 10^{-14} m

8 0
3 years ago
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