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Marina86 [1]
3 years ago
10

ANSWER FAST PLEASE. The bottom of a box has a surface area of 25.0 cm 2 . The mass of the box is 34.0 kilograms. Acceleration du

e to gravity at sea level is 9.80 m/s 2 . What pressure is exerted by the box where it rests?
A. 1.36 N/cm 2
B. 13.3 N/cm 2
C. 0.139 N/cm 2
D. 7.21 N/cm 2
Physics
2 answers:
Natasha_Volkova [10]3 years ago
7 0
34 * 9.8 = 333.2 
333.2 / 25 = 13.33

<u>B.13.3N/cm^2</u>
ohaa [14]3 years ago
5 0
13.3 is the correct answer!
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dmitriy555 [2]
20 kg.m/s
p =m*v = 5*4 = 20
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Two groups of scientists got different results while studying about the evolution of the universe. Which of these statements bes
aliya0001 [1]
The one that would explain why the two groups of scientists got different results is : 
They had different specialties and interpreted their data differently
Probably one analyze it with x theory and the other use y theory

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3 0
3 years ago
Read 2 more answers
The driver of a car slams on the brakes, causing the car to slow down at a rate of
sdas [7]

Answer:

A. The time taken for the car to stop is 3.14 secs

B. The initial velocity is 81.64 ft/s

Explanation:

Data obtained from the question include:

Acceleration (a) = 26ft/s2

Distance (s) = 256ft

Final velocity (V) = 0

Time (t) =?

Initial velocity (U) =?

A. Determination of the time taken for the car to stop.

Let us obtain an express for time (t)

Acceleration (a) = Velocity (V)/time(t)

a = V/t

Velocity (V) = distance (s) /time (t)

V = s/t

a = s/t^2

Cross multiply

a x t^2 = s

Divide both side by a

t^2 = s/a

Take the square root of both side

t = √(s/a)

Now we can obtain the time as follow

Acceleration (a) = 26ft/s2

Distance (s) = 256ft

Time (t) =..?

t = √(s/a)

t = √(256/26)

t = 3.14 secs

Therefore, the time taken for the car to stop is 3.14 secs

B. Determination of the initial speed of the car.

V = U + at

Final velocity (V) = 0

Deceleration (a) = –26ft/s2

Time (t) = 3.14 sec

Initial velocity (U) =.?

0 = U – 26x3.14

0 = U – 81.64

Collect like terms

U = 81.64 ft/s

Therefore, the initial velocity is 81.64 ft/s

7 0
3 years ago
I need help with this
ra1l [238]

What is that?? Please tell us

5 0
3 years ago
What mass of water must evaporate from the skin of a 70.0 kg man to cool his body 1.00 ∘C? The heat of vaporization of water at
romanna [79]

Answer:

100 cc

Explanation:

Heat released in cooling human body by t degree

= mass of the body x specific heat of the body x t

Substituting the data given

Heat released by the body

= 70 x 3480 x 1

= 243600 J

Mass of water to be evaporated

= 243600 / latent heat of vaporization of water

= 243600 / 2420000

= .1 kg

= 100 g

volume of water

= mass / density

= 100 / 1

100 cc

1 / 10 litres.

6 0
3 years ago
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