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Marina86 [1]
3 years ago
10

ANSWER FAST PLEASE. The bottom of a box has a surface area of 25.0 cm 2 . The mass of the box is 34.0 kilograms. Acceleration du

e to gravity at sea level is 9.80 m/s 2 . What pressure is exerted by the box where it rests?
A. 1.36 N/cm 2
B. 13.3 N/cm 2
C. 0.139 N/cm 2
D. 7.21 N/cm 2
Physics
2 answers:
Natasha_Volkova [10]3 years ago
7 0
34 * 9.8 = 333.2 
333.2 / 25 = 13.33

<u>B.13.3N/cm^2</u>
ohaa [14]3 years ago
5 0
13.3 is the correct answer!
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Please help me! Uniform acceleration problem sheet:
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From the calculation, the value of the acceleration is 5.8 m/s^2.

<h3>What is uniform acceleration?</h3>

The term uniform acceleration refers to a situation in which the velocity increases by equal amounts in equal time intervals.

Given the fact that the car started from rest and reached a velocity of  780.34 mph or 348.84 m/s in 1 minute of 60 seconds;

v = u + at

a = v/t

a = 348.84 m/s/ 60 seconds

a = 5.8 m/s^2

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2 years ago
Precision is how close a series of measurements are to ______
Leya [2.2K]

Answer:

Accuracy is how close a measured value is to an accepted value. <u>Precision is how close measurements are to one another.</u> To make measurements, you have to evaluate both the accuracy and the precision to get a correct value.

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2 years ago
A beaker of vegetable oil contains a beam of light that is aimed at a surface at an angle of 34 degrees as shown. If the index o
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Angle of reflection of light is 34 degree

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8 0
3 years ago
Two particles P and Q each moves towards ther along Straight Line (M)(N), 51m long. P starts from M with velocity 5m/s and const
bagirrra123 [75]

The time required by the particles are as follows:

a. t = 1.5 seconds

b. t = 3 seconds

c. t = 0.4 seconds

<h3>What is the time required?</h3>

The time required for the particles to be at several distances apart is calculated using the equation of motion given below:

S = ut + \frac{1}{2}at^{2}

a) Time required to be 30 m apart:

Assuming the distance covered by P is S1 and distance covered by Q is S2.

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Substituting the values of velocity and acceleration in the equation of motion above:

5t + 1/2t^2 + 6t + 3t^2 = 21

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Solving for time, t by factorization, t = 1.5 seconds

b) Time required to meet:

Assuming the distance covered by P is S1 and distance covered by Q is S2.

S1 + S2 = 51

Substituting the values of velocity and acceleration in the equation of motion above:

5t + 1/2t^2 + 6t + 3t^2 = 51

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Using the equation of motion: V = u + at

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Substituting the values:

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7 0
2 years ago
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