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noname [10]
3 years ago
12

A Person is carrying 6kg in one hand and 5kg in another.Calculate the resultant force applied by him​

Physics
1 answer:
kvasek [131]3 years ago
8 0
I think first of all you should convert both masses to weight by
W= mg ( gravity is 9.8m/s^2)

W= (6)(9.8)= 58.8N
W= (5)(9.8)= 49N

Resultant force = 58.8-49= 9.8N

Final answer:
9.8N

I’m really sorry if the answer turned out to be wrong but I tried my best so good luck!!
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C magnetism this is the answer
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A vertical scale on a spring balance reads from 0 to 155 N . The scale has a length of 10.0 cm from the 0 to 155 N reading. A fi
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Answer:

mass of the fish is 8.11 kg

Explanation:

As we know that the frequency of oscillation of spring block system is given as

f = \frac{1}{2\pi}\sqrt{\frac{k}{m}}

here we know that the reading of scale varies from 0 to 155 N from length varies from x = 0 to x = 10 cm

Now we have

k = \frac{155}{0.10} N/m

k = 1550 N/m

so now we have

2.20 = \frac{1}{2\pi}\sqrt{\frac{1550}{m}}

m = 8.11 kg

so mass of the fish is 8.11 kg

4 0
3 years ago
A balloon is filled to a volume of 7.00*10^2 mL at a temperature of 20.0°C. The balloon is then cooled at constant pressure to a
wolverine [178]

The final volume of the gas is 238.9 mL

Explanation:

We can solve this problem by using Charle's law, which states that for a gas kept at constant pressure, the volume of the gas (V) is proportional to its absolute temperature (T):

\frac{V}{T}=const.

Which can be also re-written as

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where

V_1, V_2 are the initial and final volumes of the gas

T_1, T_2 are the initial and final temperature of the gas

For the gas in the balloon in this problem, we have:

V_1 = 7.00\cdot 10^2 mL = 700 mL is the initial volume

T_1=20.0^{\circ}C+273=293 K is the initial absolute temperature

V_2 is the final volume

T_2 = 1.00\cdot 10^2 K = 100 K is the final temperature

Solving for V_2,

V_2 = \frac{V_1 T_2}{T_1}=\frac{(700)(100)}{293}=238.9 mL

Learn more about ideal gases:

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#LearnwithBrainly

6 0
3 years ago
A proton is placed in an electric field of intensity 700 N/C. What are the magnitude and direction of the acceleration of this p
olya-2409 [2.1K]

Answer:

Acceleration of proton will be a=0.67\times 10^{11}m/sec^2

Explanation:

We have given a proton is placed in an electric field of intensity of 700 N/C

So electric field E = 700 N/C

Mass of proton m=1.67\times 10^{-27}kg

Charge on proton e=1.6\times 10^{-19}C

So electric force on the proton F=qE=1.6\times 10^{-19}\times 700=1.120\times 10^{-16}N

This force will be equal to force due to acceleration of the proton

According to newton's law force is given by F = ma

So 1.67\times 10^{-27}\times a=1.120\times 10^{-16}

a=0.67\times 10^{11}m/sec^2

So acceleration of proton will be a=0.67\times 10^{11}m/sec^2

6 0
4 years ago
If a 160W light bulb consumes 1000J of electrical energy in a given time, then in the same time interval, how much energy will a
NNADVOKAT [17]
160w/4 = 40w
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a 40w light bulb will consume 250J
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3 years ago
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