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andreev551 [17]
3 years ago
14

Which description accurately describes the tide represented by the image below?

Physics
2 answers:
igomit [66]3 years ago
8 0
<span>The gravitational pull of the sun and moon combined
create larger than normal tides.</span>
luda_lava [24]3 years ago
7 0
Its the first statement:
<span>
The gravitational pull of the sun and moon combined create larger than normal tides. 
 -It's especially in this event, when the sun and moon are aligned, that the tides rise higher</span>
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Which single force acts on an object in free fall
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Answer:

gravity

Explanation:

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HELP PLEASE!! GIVING BRAINLIEST!! If you answer this correctly ill answer some of your questions you have posted! (20pts)
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Explanation:

potential energy =360800J

mass(m)=?

height (h)=25m

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we have

potential energy =360800J

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The vapor pressure of diethyl ether (ether) is 463.57 mm Hg at 25°C. How many grams of chlorophyll, C55H72MgN4O5, a nonvolatile,
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Answer:

29.4855 grams of chlorophyll

Explanation:

From Raoult's law

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Number of moles of solvent = mass/MW = 187.4/74 = 2.532 mol

Let the moles of solute (chlorophyll) be y

Total moles of solution = moles of solute + moles of solvent = (y + 2.532) mol

Mole fraction of solvent = moles of solvent/total moles of solution

0.987 = 2.532/(y + 2.532)

y + 2.532 = 2.532/0.987

y + 2.532 = 2.565

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3 years ago
All rules to find work in changing force in physics ​
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Answer:

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7 0
2 years ago
The density of nuclear matter is about 1018 kg/m3. Given that 1 mL is equal in volume to 1 cm3, what is the density of nuclear m
Sonbull [250]

Answer:

density is 10^{6} Mg/µL

Explanation:

given data

density of nuclear = 10^{18} kg/m³

1 ml = 1 cm³

to find out

density of nuclear matter in Mg/µL

solution

we know here

1 Mg = 1000 kg

so

1 m³ is equal to 10^{6} cm³

and here 1 cm³ is equal to  1 mL

so we can say 1 mL is equal to 10³ µL

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density =  10^{6} Mg/µL

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3 years ago
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