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3 years ago

Which description accurately describes the tide represented by the image below?

Physics

2 answers:

igomit [66]3 years ago

8 0

<span>The gravitational pull of the sun and moon combined
create larger than normal tides.</span>

luda_lava [24]3 years ago

7 0

Its the first statement:
<span>
The gravitational pull of the sun and moon combined create larger than normal tides.
-It's especially in this event, when the sun and moon are aligned, that the tides rise higher</span>

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MathPhys Pls PLS PLS PLS HELP ME!!!!

Katena32 [7]

Answer:

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3 years ago

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A steel wire of length 31.0 m and a copper wire of length 17.0 m, both with 1.00-mm diameters, are connected end to end and stre

Brut [27]

Answer:

The time taken is $t = 0.356 \ s$

Explanation:

From the question we are told that

The length of steel the wire is $l_1 = 31.0 \ m$

The length of the copper wire is $l_2 = 17.0 \ m$

The diameter of the wire is $d = 1.00 \ m = 1.0 *10^{-3} \ m$

The tension is $T = 122 \ N$

The time taken by the transverse wave to travel the length of the two wire is mathematically represented as

$t = t_s + t_c$

Where $t_s$ is the time taken to transverse the steel wire which is mathematically represented as

$t_s = l_1 * [ \sqrt{ \frac{\rho * \pi * d^2 }{ 4 * T} } ]$

here $\rho_s$ is the density of steel with a value $\rho_s = 8920 \ kg/m^3$

$t_s = 31 * [ \sqrt{ \frac{8920 * 3.142* (1*10^{-3})^2 }{ 4 * 122} } ]$

$t_s = 0.235 \ s$

And

$t_c$ is the time taken to transverse the copper wire which is mathematically represented as

$t_c = l_2 * [ \sqrt{ \frac{\rho_c * \pi * d^2 }{ 4 * T} } ]$

here $\rho_c$ is the density of steel with a value $\rho_s = 7860 \ kg/m^3$

$t_c = 17 * [ \sqrt{ \frac{7860 * 3.142* (1*10^{-3})^2 }{ 4 * 122} } ]$

$t_c =0.121$

$t = t_c + t_s$

$t = 0.121 + 0.235$

$t = 0.356 \ s$

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3 years ago

Why can’t you hit a feather in mid air with a force of 200 N<br> (This is all the info I was given)

Aloiza [94]

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3 years ago

________ occurs when a person is holding an object that is directly hit or splashed by lightning.

Papessa [141]

When someone is holding something that has been struck or splashed by lightning, contact damage occurs.

We need additional information concerning lightning and injuries in order to identify the solution.

<h3>What types of injuries are brought on by lightning?</h3>

Lightning is the name for a natural electrical discharge that occurs quickly and with a dazzling flash.

It has a tremendous amount of energy.

Lightning-related injuries can be divided into three categories: direct strikes, side splashes, and contact injuries.

When someone is struck by lightning directly, they can get direct injury.

When a current splashes from a neighboring object, it is called a side splash.

When someone touches a lightning-hit object, contact harm results.

In light of this, we can say that contact injuries happen when a person is holding an object that has been struck by lightning or splashed by it.

Learn more about the lightning and harm here:

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2 years ago

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A cheetah can accelerate at 4.5 m/s from rest to a speed of 30.0 m/s. Calculatethe distance

anzhelika [568]

Answer:

d= 100m

Explanation:

Cheetah kinematic

The cheetah moves with uniformly accelerated movement, and the formulas that describe this movement are:

d= v₀*t + (1/2)*a*t² Formula (1)

vf²=v₀²+2*a*d Formula (2)

vf=v₀+a*t Formula (3)

Where:

d:distance in meters (m)

v₀: initial speed in m/s

vf: final speed in m/s

a: acceleration in m/s²

t: time in seconds (s)

Known Data

v₀ =0

a = 4.5 m/s²

vf= 30 m/s.

Problem development

We apply the formula (2) that has known data to calculate the distance :

vf²=v₀²+2*a*d

(30)²= 0 + 2* 4.5* d

$d= \frac{900}{9}$

d= 100m

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3 years ago