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My name is Ann [436]
3 years ago
8

GIVING BRAINLEST TO WHOEVER GETS THE RIGHT ANSWER!! Plz and thx

Chemistry
2 answers:
LenKa [72]3 years ago
5 0

Answer:

Mechanical

Explanation:

pshichka [43]3 years ago
3 0

Answer:

mechanical

Explanation:

hope this help pls mark as brainliest

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If you are given a diagram of an atom, how would you identify what element it is?
Varvara68 [4.7K]

The simplest way to use the periodic table to identify an element is by looking for the element's name or elemental symbol. The periodic table can be used to identify an element by looking for the element's atomic number. The atomic number of an element is the number of protons found within the atoms of that element.





                                     hope it helps


7 0
3 years ago
According to the following reaction, how many grams of iron(II) chloride will be formed upon the complete reaction of 21.6 grams
velikii [3]

Answer:

37.58 g of FeCl₂.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

Fe + 2HCl —> FeCl₂ + H₂

Next, we shall determine the mass of HCl that reacted and the mass of FeCl₂ produced from the balanced equation. This is can be obtained as follow:

Molar mass of HCl = 1 + 35.5 = 36.5 g/mol

Mass of HCl from the balanced equation = 2 × 36.5 = 73 g

Molar mass of FeCl₂ = 56 + (2×35.5)

= 56 + 71

= 127 g/mol

Mass of FeCl₂ from the balanced equation = 1 × 127 = 127 g

SUMMARY:

From the balanced equation above,

73 g of HCl reacted to produced 127 g of FeCl₂.

Finally, we shall determine the mass of FeCl₂ produced by the reaction of 21.6 g of HCl. This can be obtained as follow:

From the balanced equation above,

73 g of HCl reacted to produced 127 g of FeCl₂.

Therefore, 21.6 g of HCl will react to produce = (21.6 × 127)/73 = 37.58 g of FeCl₂.

Thus, 37.58 g of FeCl₂ were obtained from the reaction.

4 0
3 years ago
A 4 L sample of gas at 298 K and 2 atm contains 0.250 mol of gas. If we add another 0.250 mol of gas at the same pressure and te
andrey2020 [161]

Answer:

V_2=8L

Explanation:

Hello there!

In this case, considering the Avogadro's gas law, which treats the volume and moles in a directly proportional way via:

\frac{V_1}{n_1}=\frac{V_2}{n_2}

Which can be solved for the final volume, V2, as shown below:

V_2=\frac{V_1n_2}{n_1}

Thus, by plugging in the given data, we obtain:

V_2=\frac{4L*(0.250mol+0.250mol)}{0.250mol}\\\\V_2=8L

Regards!

4 0
3 years ago
After 15 minutes, 30 g of a sample of polonium-218 remain unchanged. If the original sample had a mass of 960 g, what is the hal
Keith_Richards [23]
Q1. The answer is 3 minutes.

Let's first calculate the remaining amount in percent:
If 960g is 100 percent (starting amount), 30 g is how many percents:
960 g : 100% = 30 g : x
x = 30 g * 100% / 960 g = 3.125% = 0.03125

Now, using the formula to calculate the number of half-lives:
(1/2)ⁿ = x,
where
x is the remaining amount: x = 0.03125
n is the number of half-lives
1/2 stands for half-life.

(1/2)ⁿ = 0.03125
⇒ n*log(1/2) = log(0.03125) 
    n = log(0.03125)/log(1/2) = log(0.03125)/log(0.5) = -1.505/-0.301 ≈ 5

The number of half-lives is 5.
Now, <span>the number of half-lives (n) is a quotient of total time elapsed (T) and length of half-life (L):
n = T/L
We know:
n = 5
T = 15 min
L = ?

Thus
L = T/n
L = 15 min/5 = 3 minutes

Q2. Filtration should be chosen.
Filtration and distillation are used to separate mixtures - filtration for the separation of heterogeneous mixtures and </span>distillation for the separation of homogeneous mixtures. Imagine that your pile of soil is a mixture. It consists of different components (the leaves, acorns, twigs), so it is the heterogeneous mixture. Therefore, to separate the leaves, acorns, twigs you will use filtration.
5 0
4 years ago
When comparing the two chair conformations for a monosubstituted cyclohexane ring, which type of substituent shows the greatest
Klio2033 [76]

Large substituents will chose equatorial conformation over axial conformation more readily.

<h3><u>Explanation</u>:</h3>

The axial conformation of the monosubstituted cyclohexane molecule is the Conformation where the substituted group is located along the axis of the molecule, perpendicular to the plane of the molecule. The equatorial conformation on the other hand is the substituted group being aligned along the plane of the molecule.

Now, in the axial position, the large groups will face steric hindrance with the axial hydrogens of the other carbon atoms which will lead the molecule more unstable. So larger is the group, more is the steric hindrance. So larger group will prefer the equatorial conformation more readily than the axial conformation.

6 0
3 years ago
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